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JEE Main 2019
Matrices & Determinants
Matrices and Determinants
Medium

Question

If the system of linear equations x+2ay+az=0;x + 2ay + az = 0; x+3by+bz=0;x+4cy+cz=0;x + 3by + bz = 0;\,\,x + 4cy + cz = 0; has a non - zero solution, then a,b,ca, b, c.

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Solution

This problem involves a system of linear homogeneous equations. For such a system to have a non-zero (or non-trivial) solution, the determinant of the coefficient matrix must be zero. We will set up the determinant, simplify it using row and column operations, and then expand it to find the relation between a,b,ca, b, c.


1. Key Concept: Non-trivial Solution for Homogeneous System

A system of linear homogeneous equations, represented as AX=0AX = 0, where AA is the coefficient matrix, XX is the column vector of variables, and 00 is the zero vector, has a non-zero (non-trivial) solution if and only if the determinant of the coefficient matrix, det(A)\det(A), is equal to zero.

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