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JEE Main 2018
Matrices & Determinants
Matrices and Determinants
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Question

Let AA be a 2×2\,2 \times 2 matrix with non-zero entries and let A2=I,{A^2} = I, where II is 2×22 \times 2 identity matrix. Define Tr$$$$(A)= sum of diagonal elements of AA and A=\left| A \right| = determinant of matrix AA. Statement- 1: Tr$$$$(A)=0. Statement- 2: A=1\left| A \right| = 1 .

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Solution

Let A = \left( {\matrix{ a & b \cr c & d \cr } } \right) where a,b,c,da,b,c,d 0 \ne 0 {A^2} = \left( {\matrix{ a & b \cr c & d \cr } } \right)\left( {\matrix{ a & b \cr c & d \cr } } \right) \Rightarrow {A^2} = \left( {\matrix{ {{a^2} + bc} & {ab + bd} \cr {ac + cd} & {bc + {d^2}} \cr } } \right) a2+bc=1,bc+d2=1 \Rightarrow {a^2} + bc = 1,\,bc + {d^2} = 1 ab+bd=ac+cd=0ab + bd = ac + cd = 0 c0b0c \ne 0\,\,\,\,\,b \ne 0 a+d=0Tr(A)=0 \Rightarrow a + d = 0 \Rightarrow Tr\left( A \right) = 0 A=adbc=a2bc=1\left| A \right| = ad - bc = - {a^2} - bc = - 1

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