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JEE Main 2022
Matrices & Determinants
Matrices and Determinants
Medium

Question

Let A, B, C be 3 ×\times 3 matrices such that A is symmetric and B and C are skew-symmetric. Consider the statements (S1) A13^{13} B26^{26} - B26^{26} A13^{13} is symmetric (S2) A26^{26} C13^{13} - C13^{13} A26^{26} is symmetric Then,

Options

Solution

Key Concepts and Definitions

Before diving into the problem, let's recall the fundamental definitions and properties related to symmetric and skew-symmetric matrices:

  1. Symmetric Matrix: A square matrix XX is called symmetric if its transpose is equal to itself, i.e., XT=XX^T = X.
  2. Skew-Symmetric Matrix: A square matrix XX is called skew-symmetric if its transpose is equal to its negative, i.e., XT=XX^T = -X.

Important Properties of Transpose:

For any matrices XX and YY of appropriate dimensions and any scalar kk:

  • (X+Y)T=XT+YT(X+Y)^T = X^T + Y^T
  • (XY)T=YTXT(XY)^T = Y^T X^T (Note the reversal of order)
  • (kX)T=kXT(kX)^T = kX^T
  • (Xn)T=(XT)n(X^n)^T = (X^T)^n for any positive integer nn.

Properties of Powers of Symmetric/Skew-Symmetric Matrices:

  • If XX is symmetric (XT=XX^T = X), then XnX^n is always symmetric for any positive integer nn.
    • Proof: (Xn)T=(XT)n=Xn(X^n)^T = (X^T)^n = X^n.
  • If XX is skew-symmetric (XT=XX^T = -X):
    • XnX^n is symmetric if nn is an even positive integer.
      • Proof: (Xn)T=(XT)n=(X)n=(1)nXn(X^n)^T = (X^T)^n = (-X)^n = (-1)^n X^n. If nn is even, (1)n=1(-1)^n = 1, so (Xn)T=Xn(X^n)^T = X^n.
    • XnX^n is skew-symmetric if nn is an odd positive integer.
      • Proof: (Xn)T=(XT)n=(X)n=(1)nXn(X^n)^T = (X^T)^n = (-X)^n = (-1)^n X^n. If nn is odd, (1)n=1(-1)^n = -1, so (Xn)T=Xn(X^n)^T = -X^n.

Given Information

We are given three 3×33 \times 3 matrices A, B, and C with the following properties:

  • A is symmetric, which means AT=AA^T = A.
  • B is skew-symmetric, which means BT=BB^T = -B.
  • C is skew-symmetric, which means CT=CC^T = -C.

We need to evaluate the truthfulness of two statements, (S1) and (S2).


Analysis of Statement (S1)

Statement (S1) says that P=A13B26B26A13P = A^{13} B^{26} - B^{26} A^{13} is symmetric. To check this, we need to find the transpose of PP and see if it equals PP or P-P.

Step 1: Determine the nature of A13A^{13} and B26B^{26}.

  • For A13A^{13}: Since A is symmetric (AT=AA^T=A) and 1313 is an integer power, A13A^{13} will also be symmetric.
    • Let's verify: (A13)T=(AT)13=A13(A^{13})^T = (A^T)^{13} = A^{13}.
  • For B26B^{26}: Since B is skew-symmetric (BT=BB^T=-B) and 2626 is an even power, B26B^{26} will be symmetric.
    • Let's verify: (B26)T=(BT)26=(B)26=(1)26B26=1B26=B26(B^{26})^T = (B^T)^{26} = (-B)^{26} = (-1)^{26} B^{26} = 1 \cdot B^{26} = B^{26}.

So, both A13A^{13} and B26B^{26} are symmetric matrices. Let's denote X=A13X = A^{13} and Y=B26Y = B^{26}. We know XT=XX^T = X and YT=YY^T = Y.

Step 2: Calculate the transpose of PP.

We have P=XYYXP = XY - YX. Now we find PTP^T: PT=(XYYX)TP^T = (XY - YX)^T Using the property (MN)T=MTNT(M-N)^T = M^T - N^T: PT=(XY)T(YX)TP^T = (XY)^T - (YX)^T Using the property (MN)T=NTMT(MN)^T = N^T M^T for matrix products: PT=YTXTXTYTP^T = Y^T X^T - X^T Y^T Now, substitute XT=XX^T = X and YT=YY^T = Y (since both A13A^{13} and B26B^{26} are symmetric): PT=YXXYP^T = YX - XY This can be rewritten as: PT=(XYYX)P^T = -(XY - YX) Since P=XYYXP = XY - YX, we have: PT=PP^T = -P

Step 3: Conclusion for (S1).

Since PT=PP^T = -P, the matrix PP is skew-symmetric. Therefore, statement (S1) is false.


Analysis of Statement (S2)

Statement (S2) says that Q=A26C13C13A26Q = A^{26} C^{13} - C^{13} A^{26} is symmetric. Again, we find the transpose of QQ.

Step 1: Determine the nature of A26A^{26} and C13C^{13}.

  • For A26A^{26}: Since A is symmetric (AT=AA^T=A) and 2626 is an integer power, A26A^{26} will also be symmetric.
    • Let's verify: (A26)T=(AT)26=A26(A^{26})^T = (A^T)^{26} = A^{26}.
  • For C13C^{13}: Since C is skew-symmetric (CT=CC^T=-C) and 1313 is an odd power, C13C^{13} will be skew-symmetric.
    • Let's verify: (C13)T=(CT)13=(C)13=(1)13C13=C13(C^{13})^T = (C^T)^{13} = (-C)^{13} = (-1)^{13} C^{13} = -C^{13}.

So, A26A^{26} is symmetric, and C13C^{13} is skew-symmetric. Let's denote M=A26M = A^{26} and N=C13N = C^{13}. We know MT=MM^T = M and NT=NN^T = -N.

Step 2: Calculate the transpose of QQ.

We have Q=MNNMQ = MN - NM. Now we find QTQ^T: QT=(MNNM)TQ^T = (MN - NM)^T Using the property (XY)T=XTYT(X-Y)^T = X^T - Y^T: QT=(MN)T(NM)TQ^T = (MN)^T - (NM)^T Using the property (XY)T=YTXT(XY)^T = Y^T X^T for matrix products: QT=NTMTMTNTQ^T = N^T M^T - M^T N^T Now, substitute MT=MM^T = M and NT=NN^T = -N: QT=(N)MM(N)Q^T = (-N)M - M(-N) QT=NM+MNQ^T = -NM + MN This can be rewritten by rearranging the terms: QT=MNNMQ^T = MN - NM Since Q=MNNMQ = MN - NM, we have: QT=QQ^T = Q

Step 3: Conclusion for (S2).

Since QT=QQ^T = Q, the matrix QQ is symmetric. Therefore, statement (S2) is true.


Final Conclusion

Based on our analysis:

  • Statement (S1) is false.
  • Statement (S2) is true.

Comparing this with the given options, option (A) "Only S2 is true" is the correct answer.


Tips and Common Mistakes to Avoid

  1. Don't forget the order reversal for (XY)T=YTXT(XY)^T = Y^T X^T: This is a very common mistake. Always remember to reverse the order of multiplication when taking the transpose of a product.
  2. Be careful with signs when dealing with odd/even powers of skew-symmetric matrices:
    • (X)even power=Xeven power(-X)^{\text{even power}} = X^{\text{even power}}
    • (X)odd power=Xodd power(-X)^{\text{odd power}} = -X^{\text{odd power}} This distinction is critical for determining the nature of powers of skew-symmetric matrices.
  3. Understand the definitions clearly: A matrix XX is symmetric if XT=XX^T = X, and skew-symmetric if XT=XX^T = -X. Always refer back to these definitions

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