Question
Let A, B, C be 3 3 matrices such that A is symmetric and B and C are skew-symmetric. Consider the statements (S1) A B B A is symmetric (S2) A C C A is symmetric Then,
Options
Solution
Key Concepts and Definitions
Before diving into the problem, let's recall the fundamental definitions and properties related to symmetric and skew-symmetric matrices:
- Symmetric Matrix: A square matrix is called symmetric if its transpose is equal to itself, i.e., .
- Skew-Symmetric Matrix: A square matrix is called skew-symmetric if its transpose is equal to its negative, i.e., .
Important Properties of Transpose:
For any matrices and of appropriate dimensions and any scalar :
- (Note the reversal of order)
- for any positive integer .
Properties of Powers of Symmetric/Skew-Symmetric Matrices:
- If is symmetric (), then is always symmetric for any positive integer .
- Proof: .
- If is skew-symmetric ():
- is symmetric if is an even positive integer.
- Proof: . If is even, , so .
- is skew-symmetric if is an odd positive integer.
- Proof: . If is odd, , so .
- is symmetric if is an even positive integer.
Given Information
We are given three matrices A, B, and C with the following properties:
- A is symmetric, which means .
- B is skew-symmetric, which means .
- C is skew-symmetric, which means .
We need to evaluate the truthfulness of two statements, (S1) and (S2).
Analysis of Statement (S1)
Statement (S1) says that is symmetric. To check this, we need to find the transpose of and see if it equals or .
Step 1: Determine the nature of and .
- For : Since A is symmetric () and is an integer power, will also be symmetric.
- Let's verify: .
- For : Since B is skew-symmetric () and is an even power, will be symmetric.
- Let's verify: .
So, both and are symmetric matrices. Let's denote and . We know and .
Step 2: Calculate the transpose of .
We have . Now we find : Using the property : Using the property for matrix products: Now, substitute and (since both and are symmetric): This can be rewritten as: Since , we have:
Step 3: Conclusion for (S1).
Since , the matrix is skew-symmetric. Therefore, statement (S1) is false.
Analysis of Statement (S2)
Statement (S2) says that is symmetric. Again, we find the transpose of .
Step 1: Determine the nature of and .
- For : Since A is symmetric () and is an integer power, will also be symmetric.
- Let's verify: .
- For : Since C is skew-symmetric () and is an odd power, will be skew-symmetric.
- Let's verify: .
So, is symmetric, and is skew-symmetric. Let's denote and . We know and .
Step 2: Calculate the transpose of .
We have . Now we find : Using the property : Using the property for matrix products: Now, substitute and : This can be rewritten by rearranging the terms: Since , we have:
Step 3: Conclusion for (S2).
Since , the matrix is symmetric. Therefore, statement (S2) is true.
Final Conclusion
Based on our analysis:
- Statement (S1) is false.
- Statement (S2) is true.
Comparing this with the given options, option (A) "Only S2 is true" is the correct answer.
Tips and Common Mistakes to Avoid
- Don't forget the order reversal for : This is a very common mistake. Always remember to reverse the order of multiplication when taking the transpose of a product.
- Be careful with signs when dealing with odd/even powers of skew-symmetric matrices:
- This distinction is critical for determining the nature of powers of skew-symmetric matrices.
- Understand the definitions clearly: A matrix is symmetric if , and skew-symmetric if . Always refer back to these definitions