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JEE Main 2021
Matrices & Determinants
Matrices and Determinants
Hard

Question

Let AA be a 3×33 \times 3 real matrix such that A(101)=2(101),A(101)=4(101),A(010)=2(010)A\left(\begin{array}{l} 1 \\ 0 \\ 1 \end{array}\right)=2\left(\begin{array}{l} 1 \\ 0 \\ 1 \end{array}\right), A\left(\begin{array}{l} -1 \\ 0 \\ 1 \end{array}\right)=4\left(\begin{array}{l} -1 \\ 0 \\ 1 \end{array}\right), A\left(\begin{array}{l} 0 \\ 1 \\ 0 \end{array}\right)=2\left(\begin{array}{l} 0 \\ 1 \\ 0 \end{array}\right) \text {. } Then, the system (A3I)(xyz)=(123)(A-3 I)\left(\begin{array}{l}x \\ y \\ z\end{array}\right)=\left(\begin{array}{l}1 \\ 2 \\ 3\end{array}\right) has :

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Solution

This problem beautifully combines concepts of eigenvalues, eigenvectors, and solving systems of linear equations. The key is to first understand the structure of the given information about matrix AA and then use it to determine the properties of the system (A3I)x=b(A-3I)\mathbf{x} = \mathbf{b}.


1. Key Concepts

  • Eigenvalues and Eigenvectors: A non-zero vector v\mathbf{v} is an eigenvector of a square matrix AA if Av=λvA\mathbf{v} = \lambda\mathbf{v} for some scalar λ\lambda. The scalar λ\lambda is called the eigenvalue corresponding to v\mathbf{v}.
  • Linear Independence: A set of vectors is linearly independent if no vector in the set can be written as

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