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JEE Main 2022
Matrices & Determinants
Matrices and Determinants
Medium

Question

Let A=(1225)A=\left(\begin{array}{cc}1 & 2 \\ -2 & -5\end{array}\right). Let α,βR\alpha, \beta \in \mathbb{R} be such that αA2+βA=2I\alpha A^{2}+\beta A=2 I. Then α+β\alpha+\beta is equal to

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Solution

Here is a detailed, step-by-step solution to the problem, incorporating explanations, tips, and an alternative method using the Cayley-Hamilton Theorem.


1. Understanding the Problem and Key Concepts

The problem asks us to find the sum α+β\alpha + \beta given a matrix AA and a matrix equation αA2+βA=2I\alpha A^2 + \beta A = 2I. To solve this, we will primarily use the following matrix operations:

  • Matrix Multiplication: To calculate A2A^2.
  • Scalar Multiplication of Matrices: To find αA2\alpha A^2 and βA\beta A.
  • Matrix Addition: To sum αA2\alpha A^2 and βA\beta A.
  • Matrix Equality: To equate the resulting matrix with 2I2I and form a system of linear equations.
  • Identity Matrix (II): For a 2×22 \times 2 matrix, I=(1001)I = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}. Thus, 2I=(2002)2I = \begin{pmatrix} 2 & 0 \\ 0 & 2 \end{pmatrix}.

An alternative, often more elegant approach for problems involving powers of a matrix, is the Cayley-Hamilton Theorem, which states that every square matrix satisfies its own characteristic equation

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