Question
Let M and m respectively be the maximum and the minimum values of Then is equal to :
Options
Solution
Key Concepts and Formulas
This problem primarily involves the following mathematical concepts:
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Properties of Determinants:
- Row/Column Operations: The value of a determinant remains unchanged if we apply the operation (or ) where and are rows (or and are columns). This property is crucial for simplifying determinants by introducing zeros.
- Expansion of a Determinant: For a matrix , its determinant can be expanded along the first row as . Expanding along any row or column yields the same result.
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Trigonometric Identities:
- The fundamental identity: .
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Range of Trigonometric Functions:
- For any real number , the sine function satisfies . This property is used to find the maximum and minimum values of the function.
Step-by-Step Solution
Step 1: Simplify the Determinant using Row Operations
We are given the function as a determinant:
Our goal is to simplify this determinant. A common strategy is to introduce zeros into rows or columns using row/column operations, which significantly eases the expansion process. Observe that the first two columns have similar terms in different rows. We can perform row operations to simplify these terms.
Let's apply the following row operations:
Why these operations? These operations are chosen because they will create simple entries (including zeros) in the second and third rows, especially in the first two columns. For example, in the second row, the first element will become , and the second element will become . Similarly for the third row. These operations do not change the value of the determinant.
Let's apply them: For :
For :
After applying these operations, the determinant becomes:
Step 2: Expand the Simplified Determinant
Now that we have a simplified determinant with zeros, we can expand it. We can expand along any row or column. Expanding along (as in the original solution) or or (due to the presence of zeros) would be efficient. Let's expand along :
Where .
- The minor for is .
- The minor for is .
- The minor for is .
Substituting these values into the expansion:
Why this simplification? We use the fundamental trigonometric identity . This is the simplified form of the function .
Step 3: Determine the Maximum (M) and Minimum (m) Values of
We have . To find the maximum and minimum values of , we need to consider the range of the sine function. We know that for any real value (in our case, ):
Now, we build up the expression for using this inequality: First, multiply by 4: Next, add 2 to all parts of the inequality:
From this inequality, we can identify the maximum and minimum values of :
- Maximum value,
- Minimum value,
Step 4: Calculate
Finally, we need to calculate the value of :
Calculate the powers:
Substitute these values:
Thus, the value of is 1280.
Tips for Students & Common Mistakes to Avoid
- Prioritize Simplification: Always look for opportunities to simplify determinants using row or column operations before expanding. This reduces the number of terms and the chances of calculation errors. Operations like (or ) are powerful because they do not change the determinant's value.
- Trigonometric Identities are Key: Keep fundamental trigonometric identities like handy. They often appear in these problems to simplify expressions.
- Range of Functions: When finding maximum/minimum values, remember the basic ranges of trigonometric functions. For and , the range is . Be careful when multiplying or adding constants to these inequalities.
- Powers of Negative Numbers: Pay attention to signs when calculating powers of negative numbers. An even power of a negative number results in a positive number (e.g., ), while an odd power results in a negative number.
- Careful Expansion: When expanding a determinant, remember the alternating signs of the cofactors. If expanding along , the signs are
+ - +.
Summary and Key Takeaway
This problem is an excellent illustration of how different mathematical topics—matrices and determinants, trigonometry, and functions—can be integrated into a single question. The most efficient path to the solution involves:
- Strategically applying row/column operations to simplify the determinant.
- Using trigonometric identities