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Permutations & Combinations
Permutations and Combinations
Easy

Question

Number of ways of arranging 8 identical books into 4 identical shelves where any number of shelves may remain empty is equal to

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Solution

Key Concepts and Formulas

  • Partitioning: The problem is equivalent to partitioning the number 8 into at most 4 parts. Since the shelves are identical, the order of the parts doesn't matter.
  • Integer Partition: Finding the number of ways to write a positive integer nn as a sum of positive integers. The order of the summands does not matter.

Step-by-Step Solution

Step 1: Consider the case where three shelves are empty.

  • Why: This is the simplest case to analyze. We are distributing all 8 books onto a single shelf.
  • Math: (8, 0, 0, 0)
  • Reasoning: Since the shelves are identical, there's only one way to put all 8 books on one shelf and leave the other three empty.

Step 2: Consider the case where two shelves are empty.

  • Why: We are now distributing the 8 books onto two shelves. We need to find all possible combinations of books on the two shelves.
  • Math:
    • (7, 1, 0, 0)
    • (6, 2, 0, 0)
    • (5, 3, 0, 0)
    • (4, 4, 0, 0)
  • Reasoning: We need to find all pairs of positive integers that sum to 8. Since the shelves are identical, (7, 1, 0, 0) is the same as (1, 7, 0, 0). Thus, we only need to consider cases where the first number is greater than or equal to the second. This gives us 4 possible arrangements.

Step 3: Consider the case where one shelf is empty.

  • Why: We are now distributing the 8 books onto three shelves. We need to find all possible combinations of books on the three shelves.
  • Math:
    • (6, 1, 1, 0)
    • (5, 2, 1, 0)
    • (4, 3, 1, 0)
    • (4, 2, 2, 0)
    • (3, 3, 2, 0)
  • Reasoning: We need to find all triples of positive integers that sum to 8. Again, since the shelves are identical, the order doesn't matter. We can list them systematically, ensuring that the first number is greater than or equal to the second, and the second is greater than or equal to the third. This gives us 5 possible arrangements.

Step 4: Consider the case where no shelves are empty.

  • Why: We are now distributing the 8 books onto four shelves, with each shelf having at least one book. We need to find all possible combinations of books on the four shelves.
  • Math:
    • (5, 1, 1, 1)
    • (4, 2, 1, 1)
    • (3, 3, 1, 1)
    • (3, 2, 2, 1)
    • (2, 2, 2, 2)
  • Reasoning: We need to find all quadruples of positive integers that sum to 8. The order doesn't matter. We can list them systematically, ensuring the numbers are in descending order. This gives us 5 possible arrangements.

Step 5: Calculate the total number of ways.

  • Why: We sum the number of ways for each case (3 shelves empty, 2 shelves empty, 1 shelf empty, and no shelves empty).
  • Math: 1 + 4 + 5 + 5 = 15
  • Reasoning: This is the sum of the number of possibilities from each distinct case, giving the total number of arrangements. This is incorrect, the correct total should be 15. Let's re-examine each step.

Re-evaluating Step 4: Case where no shelves are empty

  • Why: We need to ensure we have all possible combinations of 4 positive integers that sum to 8.
  • Math:
    • (5, 1, 1, 1)
    • (4, 2, 1, 1)
    • (3, 3, 1, 1)
    • (3, 2, 2, 1)
    • (2, 2, 2, 2)
  • Reasoning: These are indeed all the unique combinations of 4 positive integers that add up to 8, where order doesn't matter. So, there are 5 ways.

Re-evaluating Step 3: Case where one shelf is empty

  • Why: We need to ensure we have all possible combinations of 3 positive integers that sum to 8.
  • Math:
    • (6, 1, 1, 0)
    • (5, 2, 1, 0)
    • (4, 3, 1, 0)
    • (4, 2, 2, 0)
    • (3, 3, 2, 0)
  • Reasoning: These are indeed all the unique combinations of 3 positive integers that add up to 8, where order doesn't matter. So, there are 5 ways.

Re-evaluating Step 2: Case where two shelves are empty

  • Why: We need to ensure we have all possible combinations of 2 positive integers that sum to 8.
  • Math:
    • (7, 1, 0, 0)
    • (6, 2, 0, 0)
    • (5, 3, 0, 0)
    • (4, 4, 0, 0)
  • Reasoning: These are indeed all the unique combinations of 2 positive integers that add up to 8, where order doesn't matter. So, there are 4 ways.

Re-evaluating Step 1: Case where three shelves are empty

  • Why: We need to ensure we have all possible combinations of 1 positive integer that sums to 8.
  • Math:
    • (8, 0, 0, 0)
  • Reasoning: There is only one way to put all 8 books on one shelf. So, there is 1 way.

Corrected Step 5: Calculate the total number of ways.

  • Math: 1 + 4 + 5 + 5 = 15. Still incorrect!

Let's list ALL possible partitions of 8 into at most 4 parts. 8 7+1 6+2 6+1+1 5+3 5+2+1 5+1+1+1 4+4 4+3+1 4+2+2 4+2+1+1 3+3+2 3+3+1+1 3+2+2+1 2+2+2+2

There are 15 possibilities.

This method is prone to error. A better approach is to consider the number of parts and derive the possibilities.

Number of parts = 1: (8) - 1 way Number of parts = 2: (7,1), (6,2), (5,3), (4,4) - 4 ways Number of parts = 3: (6,1,1), (5,2,1), (4,3,1), (4,2,2), (3,3,2) - 5 ways Number of parts = 4: (5,1,1,1), (4,2,1,1), (3,3,1,1), (3,2,2,1), (2,2,2,2) - 5 ways

Total = 1 + 4 + 5 + 5 = 15.

The problem statement is wrong. The correct answer is 15. The correct answer is not 18.

A possible misinterpretation:

The correct answer is likely 15, but the listed answer is 18. Perhaps there's a misunderstanding of the problem statement, or a typo. However, based on the standard interpretation of arranging identical items into identical containers, our calculation of 15 should be correct. Let's try to force the answer to be 18. If the books were distinct then the problem becomes extremely complex.

If instead, the correct answer is indeed 18, it requires a different interpretation of the problem statement.

Since we are given that the correct answer is 18, and our current calculations yield 15, there is likely an error. We cannot reconcile the given solution with the correct answer of 18.

Let's revisit the partitions of 8 into at most 4 parts.

Partitions of 8: 8 7+1 6+2 5+3 4+4 6+1+1 5+2+1 4+3+1 4+2+2 3+3+2 5+1+1+1 4+2+1+1 3+3+1+1 3+2+2+1 2+2+2+2

Total: 15.

The correct answer must be 15.

Common Mistakes & Tips

  • Double-counting: When listing the possibilities, ensure that you are not double-counting arrangements due to the identical shelves.
  • Systematic Listing: List the partitions systematically to avoid missing any possibilities. Start with the largest possible number and work your way down.
  • Incorrect Problem Interpretation: Always make sure you fully understand the question before attempting a solution.

Summary

The problem asks for the number of ways to arrange 8 identical books into 4 identical shelves, where any number of shelves may remain empty. This is equivalent to finding the number of partitions of the integer 8 into at most 4 parts. By systematically listing all possible partitions, we find that there are 15 such arrangements. Despite the provided "Correct Answer" being 18, our thorough analysis shows the correct answer is 15.

Final Answer The final answer is \boxed{15}, which does not correspond to any of the given options. The question or the answer provided is flawed.

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