JEE Main 2019Properties of TriangleProperties of TriangleEasyQuestionThe sum of the radii of inscribed and circumscribed circles for an nnn sided regular polygon of side a,a, a, is :OptionsAa4cot(π2n){a \over 4}\cot \left( {{\pi \over {2n}}} \right)4acot(2nπ)Bacot(πn)a\cot \left( {{\pi \over {n}}} \right)acot(nπ)Ca2cot(π2n){a \over 2}\cot \left( {{\pi \over {2n}}} \right)2acot(2nπ)Dacot(π2n)a\cot \left( {{\pi \over {2n}}} \right)acot(2nπ)Check AnswerHide SolutionSolutiontan(πn)=a2r; sin(πn)=a2R\tan \left( {{\pi \over n}} \right) = {a \over {2r}};\,\,\sin \left( {{\pi \over n}} \right) = {a \over {2R}}tan(nπ)=2ra;sin(nπ)=2Ra r+R=a2[cotπn+cosecπn]r + R = {a \over 2}\left[ {\cot {\pi \over n} + \cos ec{\pi \over n}} \right]r+R=2a[cotnπ+cosecnπ] =a2[cosπn+1sinπn] = {a \over 2}\left[ {{{\cos {\pi \over n} + 1} \over {\sin {\pi \over n}}}} \right]=2a[sinnπcosnπ+1] =a2[2cos2π2n2sinπ2ncosπ2n] = {a \over 2}\left[ {{{2{{\cos }^2}{\pi \over {2n}}} \over {2\sin {\pi \over {2n}}\cos {\pi \over {2n}}}}} \right]=2a[2sin2nπcos2nπ2cos22nπ] =a2cotπ2π = {a \over 2}\cot {\pi \over {2\pi }}=2acot2ππ