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JEE Main 2019
Quadratic Equations
Quadratic Equation and Inequalities
Easy

Question

If one real root of the quadratic equation 81x 2 + kx + 256 = 0 is cube of the other root, then a value of k is

Options

Solution

Key Concepts and Formulas

  • Vieta's Formulas: For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 with roots α\alpha and β\beta, the sum of the roots is α+β=ba\alpha + \beta = -\frac{b}{a} and the product of the roots is αβ=ca\alpha \beta = \frac{c}{a}.
  • Relationship between Roots: Understanding how the roots are related to each other is crucial. In this case, one root is the cube of the other (β=α3\beta = \alpha^3).
  • Fourth Root: The fourth root of a positive number has both positive and negative real solutions.

Step-by-Step Solution

Step 1: Define the Roots and Set Up the Problem

We are given the quadratic equation 81x2+kx+256=081x^2 + kx + 256 = 0. Let the roots be α\alpha and β\beta, where β=α3\beta = \alpha^3. Our goal is to find a possible value of kk.

Step 2: Apply Vieta's Formula for the Product of Roots

Using Vieta's formulas, the product of the roots is given by: αβ=ca\alpha \beta = \frac{c}{a} Substituting β=α3\beta = \alpha^3, a=81a = 81, and c=256c = 256, we get: α(α3)=25681\alpha (\alpha^3) = \frac{256}{81} α4=25681\alpha^4 = \frac{256}{81} Taking the fourth root of both sides: α=±256814=±2564814=±43\alpha = \pm \sqrt[4]{\frac{256}{81}} = \pm \frac{\sqrt[4]{256}}{\sqrt[4]{81}} = \pm \frac{4}{3} Thus, α\alpha can be either 43\frac{4}{3} or 43-\frac{4}{3}.

Step 3: Apply Vieta's Formula for the Sum of Roots

Using Vieta's formulas, the sum of the roots is given by: α+β=ba\alpha + \beta = -\frac{b}{a} Substituting β=α3\beta = \alpha^3, a=81a = 81, and b=kb = k, we get: α+α3=k81\alpha + \alpha^3 = -\frac{k}{81} k=81(α+α3)k = -81(\alpha + \alpha^3)

Step 4: Calculate k for α=43\alpha = \frac{4}{3}

If α=43\alpha = \frac{4}{3}, then α3=(43)3=6427\alpha^3 = \left(\frac{4}{3}\right)^3 = \frac{64}{27}. Substituting into the equation for kk: k=81(43+6427)=81(3627+6427)=81(10027)k = -81\left(\frac{4}{3} + \frac{64}{27}\right) = -81\left(\frac{36}{27} + \frac{64}{27}\right) = -81\left(\frac{100}{27}\right) k=3(100)=300k = -3(100) = -300

Step 5: Calculate k for α=43\alpha = -\frac{4}{3}

If α=43\alpha = -\frac{4}{3}, then α3=(43)3=6427\alpha^3 = \left(-\frac{4}{3}\right)^3 = -\frac{64}{27}. Substituting into the equation for kk: k=81(436427)=81(36276427)=81(10027)k = -81\left(-\frac{4}{3} - \frac{64}{27}\right) = -81\left(-\frac{36}{27} - \frac{64}{27}\right) = -81\left(-\frac{100}{27}\right) k=3(100)=300k = 3(100) = 300

Step 6: Determine the Correct Option

We have found two possible values for kk: 300-300 and 300300. The question asks for a value of kk. Comparing these values with the given options, we see that option (B) is 300-300, which is one of our calculated values.

Common Mistakes & Tips

  • Sign Errors: Pay close attention to signs, especially when dealing with negative roots and cubing them.
  • Forgetting ±\pm: Remember to consider both positive and negative roots when taking the fourth root.
  • Arithmetic: Double-check your arithmetic, especially when dealing with fractions.

Summary

We used Vieta's formulas to relate the roots and coefficients of the quadratic equation. By using the product of the roots, we found the possible values of α\alpha. Then, using the sum of the roots, we found the possible values of kk. The possible values for kk were 300-300 and 300300, and 300-300 is one of the answer choices.

The final answer is \boxed{-300}, which corresponds to option (B).

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