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JEE Main 2018
Quadratic Equations
Quadratic Equation and Inequalities
Easy

Question

If the roots of the equation x2bx+c=0{x^2} - bx + c = 0 be two consecutive integers, then b24c{b^2} - 4c equals

Options

Solution

Key Concepts and Formulas

  • Vieta's Formulas: For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is b/a-b/a and the product of the roots is c/ac/a.
  • Consecutive Integers: If nn is an integer, then nn and n+1n+1 are consecutive integers.
  • Discriminant: The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by b24acb^2 - 4ac.

Step-by-Step Solution

Step 1: Define the roots. Let the two consecutive integer roots be nn and n+1n+1, where nn is an integer.

  • Why: This step translates the problem's condition "roots are two consecutive integers" into a mathematical representation using a variable.

Step 2: Apply Vieta's Formulas. For the quadratic equation x2bx+c=0x^2 - bx + c = 0, we have a=1a = 1. Applying Vieta's formulas:

  • Sum of Roots: The sum of the roots is n+(n+1)n + (n+1). According to Vieta's formulas, this is equal to bb. n+(n+1)=bn + (n+1) = b Simplifying gives: 2n+1=b2n + 1 = b

    • Why: This equation expresses the coefficient bb in terms of the integer nn.
  • Product of Roots: The product of the roots is n(n+1)n(n+1). According to Vieta's formulas, this is equal to cc. n(n+1)=cn(n+1) = c

    • Why: This equation expresses the coefficient cc in terms of the integer nn.

Step 3: Substitute into the target expression. We want to find the value of b24cb^2 - 4c. Substitute the expressions for bb and cc from Step 2: b24c=(2n+1)24(n(n+1))b^2 - 4c = (2n+1)^2 - 4(n(n+1))

  • Why: This substitution expresses the target expression in terms of a single variable, nn, facilitating simplification.

Step 4: Expand and simplify. Expand the terms: (2n+1)2=4n2+4n+1(2n+1)^2 = 4n^2 + 4n + 1 4(n(n+1))=4n2+4n4(n(n+1)) = 4n^2 + 4n Substitute back into the expression: b24c=(4n2+4n+1)(4n2+4n)b^2 - 4c = (4n^2 + 4n + 1) - (4n^2 + 4n)

  • Why: Expanding the terms allows for simplification by combining like terms.

Step 5: Perform the final calculation. Simplify the expression: b24c=4n2+4n+14n24nb^2 - 4c = 4n^2 + 4n + 1 - 4n^2 - 4n b24c=1b^2 - 4c = 1

  • Why: The cancellation of terms involving nn demonstrates that the value of b24cb^2 - 4c is constant and independent of the specific integer value of nn.

Common Mistakes & Tips

  • Vieta's Formulas: Ensure you apply Vieta's formulas correctly, especially regarding the signs.
  • Algebraic Manipulation: Double-check your algebraic expansions and simplifications to avoid errors.
  • Discriminant Interpretation: Recognizing that b24cb^2 - 4c is the discriminant can provide context, but is not strictly required to solve the problem.

Summary Given that the roots of the equation x2bx+c=0x^2 - bx + c = 0 are consecutive integers, we represented the roots as nn and n+1n+1. By applying Vieta's formulas, we found expressions for bb and cc in terms of nn. Substituting these into the expression b24cb^2 - 4c and simplifying, we found that b24c=1b^2 - 4c = 1.

Final Answer The final answer is 1\boxed{1}, which corresponds to option (D).

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