Question
Let be the three roots of the equation . If , then is equal to :
Options
Solution
Key Concepts and Formulas
- Vieta's Formulas: For a cubic equation with roots :
- Roots of Unity: The solutions to are , where is a complex cube root of unity. Key properties include and .
Step-by-Step Solution
Step 1: Determine the value of using the product of roots.
We are given that are the roots of . From Vieta's formulas, the product of the roots is . We are also given that and .
- Reasoning: The product of the roots formula relates the roots to the constant term . We can use the given conditions for to find the value of .
Substituting and into the product of roots formula: Therefore,
Step 2: Determine the value of using the fact that is a root.
Since is a root of the equation , it must satisfy the equation when substituted for .
- Reasoning: If a value is a root of an equation, substituting it into the equation will result in the equation being equal to zero. This allows us to find the coefficient .
Substituting into the equation: Substituting the value of that we found in Step 1: Therefore,
Step 3: Identify the cubic equation and its roots.
Now that we have and , the original cubic equation becomes: This can be rewritten as .
- Reasoning: By finding the coefficients and , we have determined the specific cubic equation. Recognizing this equation as is crucial because its roots are standard complex numbers related to the cube roots of unity.
The roots of are , where is a complex cube root of unity. We already know that one root is . Therefore, the other two roots, and , must be and . Let's verify this assignment with the given condition : If we assign and : Since , we have: This is consistent with the given condition. So, we have:
Step 4: Evaluate the given expression.
We need to calculate the value of the expression:
- Reasoning: With all the roots and coefficients determined, we can now substitute these values into the target expression. The properties of will be essential for simplifying terms like and .
Substituting the values: , , , , : Simplifying each term:
Now, substitute these simplified terms back into the expression:
Common Mistakes & Tips
- Sign Errors in Vieta's Formulas: Ensure correct signs. The product of roots is for .
- Incorrect Identification of Cube Roots of Unity: Remember the roots of are .
- Powers of : Use to simplify higher powers.
Summary
We used Vieta's formulas and the properties of cube roots of unity to solve this problem. We first determined the coefficients and of the cubic equation. Then, using the fact that , we identified the roots . Finally, we substituted these values into the given expression and simplified to find the result.
The final answer is \boxed{19}, which corresponds to option (B).