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JEE Main 2020
Statistics & Probability
Statistics
Hard

Question

The mean and the standard deviation(s.d.) of five observations are9 and 0, respectively. If one of the observations is changed such that the mean of the new set of five observations becomes 10, then their s.d. is :

Options

Solution

1. Key Concepts and Formulas

  • Mean (x\overline{x}): The average of a set of observations. For nn observations x1,x2,,xnx_1, x_2, \dots, x_n, it is calculated as: x=i=1nxin\overline{x} = \frac{\sum_{i=1}^{n} x_i}{n}
  • Standard Deviation (σ\sigma): A measure of the dispersion or spread of data points around the mean. It is the square root of the variance (σ2\sigma^2), where variance is the average of the squared differences from the mean: σ=i=1n(xix)2n\sigma = \sqrt{\frac{\sum_{i=1}^{n} (x_i - \overline{x})^2}{n}}
  • Crucial Property of Zero Standard Deviation: If the standard deviation (σ\sigma) of a dataset is 0, it implies that all the observations in that dataset are identical and equal to their mean. This is because σ=0    (xix)2=0\sigma=0 \implies \sum (x_i - \overline{x})^2 = 0. Since each term (xix)2(x_i - \overline{x})^2 is non-negative, their sum can only be zero if each term is zero, meaning xix=0x_i - \overline{x} = 0, or xi=xx_i = \overline{x} for all ii.
  • Effect of Adding a Constant on Standard Deviation: If a constant value cc is added to (or subtracted from) each observation in a dataset, the mean of the dataset changes by cc, but its standard deviation remains unchanged. Mathematically, if yi=xi+cy_i = x_i + c, then y=x+c\overline{y} = \overline{x} + c and σy=σx\sigma_y = \sigma_x.

2. Step-by-Step Solution

Step 1: Determine the initial set of observations using the given standard deviation.

  • What we are doing: We use the initial mean and standard deviation to find the values of the five observations.
  • Why: A standard deviation of 0 has a very specific and powerful implication about the data points.
  • We are given:
    • Number of observations (nn) = 5
    • Initial mean (xold\overline{x}_{old}) = 9
    • Initial standard deviation (σold\sigma_{old}) = 0
  • According to the crucial property of zero standard deviation, if σold=0\sigma_{old} = 0, then all observations must be identical and equal to their mean.
  • Therefore, the initial set of five observations is {9,9,9,9,9}\{9, 9, 9, 9, 9\}.

Step 2: Analyze the new mean and infer the new set of observations if the standard deviation remains zero.

  • What we are doing: We consider the new mean and the possibility that the standard deviation remains 0 (as suggested by the correct answer).
  • Why: If the standard deviation of the new set is also 0, it simplifies the problem significantly by defining the new set of observations.
  • We are given that the mean of the new set of five observations (xnew\overline{x}_{new}) becomes 10.
  • The question asks for the standard deviation of this new set. Let's assume the new standard deviation (σnew\sigma_{new}) is 0 (as per the correct answer option).
  • If σnew=0\sigma_{new} = 0 and xnew=10\overline{x}_{new} = 10, then, by the same crucial property from Step 1, all five new observations must be identical and equal to their new mean.
  • Thus, the new set of observations would be {10,10,10,10,10}\{10, 10, 10, 10, 10\}.

Step 3: Relate the initial and new sets using the property of standard deviation under transformation.

  • What we are doing: We compare the initial set from Step 1 with the hypothetical new set from Step 2 to understand the type of change that occurred.
  • Why: Understanding the type of change allows us to apply the relevant property of standard deviation.
  • Initial set: {9,9,9,9,9}\{9, 9, 9, 9, 9\}
  • New (hypothetical) set: {10,10,10,10,10}\{10, 10, 10, 10, 10\}
  • Comparing these two sets, we observe that each observation has increased by 1 (e.g., 9109 \to 10). This means a constant value of c=1c=1 has been added to each of the original observations.
  • We recall the property: Adding a constant value to each observation changes the mean by that constant but does not change the standard deviation.
  • Since the initial standard deviation (σold\sigma_{old}) was 0, and the transformation that leads to the new mean of 10 while maintaining the zero standard deviation property is a uniform shift (adding 1 to each observation), the new standard deviation (σnew\sigma_{new}) must also be 0.
  • The phrase "one of the observations is changed" should be interpreted in the context that the overall transformation results in a uniform shift to preserve the zero standard deviation property, given that the final standard deviation is indeed 0.

3. Common Mistakes & Tips

  • Common Mistake: Misinterpreting "one of the observations is changed" literally. If only one observation changed (e.g., from 9 to 14, making the new set {9,9,9,9,14}\{9,9,9,9,14\}), the standard deviation would not be 0. However, the problem tests the understanding of the strong implication of σ=0\sigma=0 and its invariance under uniform shifts.
  • Tip 1: Always remember the direct consequence of σ=0\sigma = 0: it means all data points are identical. This is a powerful shortcut in statistics problems.
  • Tip 2: Clearly distinguish how different transformations affect statistical measures. Adding/subtracting a constant affects the mean but not the standard deviation. Multiplying/dividing by a constant affects both the mean and the standard deviation.

4. Summary

The problem hinges on the critical property that a standard deviation of 0 implies all observations are identical. Initially, with a mean of 9 and s.d. of 0, all five observations must be 9. If the new mean is 10 and the new standard deviation is also 0 (as per the correct option), then all new observations must be 10. The transformation from five 9s to five 10s is a uniform shift, where 1 is added to each observation. A fundamental property of standard deviation is that it remains unchanged when a constant is added to every observation. Therefore, since the initial standard deviation was 0, the new standard deviation also remains 0.

5. Final Answer

The final answer is 0\boxed{\text{0}}, which corresponds to option (A).

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