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JEE Main 2019
Straight Lines
Straight Lines and Pair of Straight Lines
Easy

Question

A straight line through the point A(3,4)A (3, 4) is such that its intercept between the axes is bisected at AA. Its equation is :

Options

Solution

Key Concepts and Formulas

  • Intercept Form of a Straight Line: A line with x-intercept aa and y-intercept bb has the equation: xa+yb=1\frac{x}{a} + \frac{y}{b} = 1
  • Midpoint Formula: The midpoint MM of a line segment with endpoints P(x1,y1)P(x_1, y_1) and Q(x2,y2)Q(x_2, y_2) is given by: M=(x1+x22,y1+y22)M = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Step-by-Step Solution

Step 1: Define the line using the intercept form.

  • We are given information about the x and y intercepts, so we will use the intercept form of a line.
  • Let the equation of the straight line be xa+yb=1\frac{x}{a} + \frac{y}{b} = 1.
  • Here, aa is the x-intercept, so the line crosses the x-axis at the point (a,0)(a, 0).
  • And bb is the y-intercept, so the line crosses the y-axis at the point (0,b)(0, b).

Step 2: Apply the given condition that A(3, 4) bisects the intercept.

  • The problem states that the point A(3,4)A(3, 4) bisects the line segment between the x and y intercepts. This means that A(3,4)A(3, 4) is the midpoint of the line segment connecting the points (a,0)(a, 0) and (0,b)(0, b).
  • We will use the midpoint formula to relate the coordinates of the intercepts to the coordinates of point AA.

Step 3: Use the Midpoint Formula to set up equations for aa and bb.

  • Using the midpoint formula for the segment with endpoints (a,0)(a, 0) and (0,b)(0, b), the midpoint's coordinates are: (a+02,0+b2)=(a2,b2)\left(\frac{a+0}{2}, \frac{0+b}{2}\right) = \left(\frac{a}{2}, \frac{b}{2}\right)
  • Since this midpoint is given as A(3,4)A(3, 4), we can equate the corresponding coordinates: a2=3andb2=4\frac{a}{2} = 3 \quad \text{and} \quad \frac{b}{2} = 4

Step 4: Solve for the x-intercept (aa) and y-intercept (bb).

  • From the equation a2=3\frac{a}{2} = 3, we multiply both sides by 2 to solve for aa: a=3×2    a=6a = 3 \times 2 \implies a = 6
  • From the equation b2=4\frac{b}{2} = 4, we multiply both sides by 2 to solve for bb: b=4×2    b=8b = 4 \times 2 \implies b = 8
  • So, the x-intercept of the line is 66, and the y-intercept is 88.

Step 5: Substitute the values of aa and bb back into the intercept form of the line's equation.

  • Now that we have a=6a=6 and b=8b=8, we can write the equation of the line as: x6+y8=1\frac{x}{6} + \frac{y}{8} = 1

Step 6: Simplify the equation.

  • To eliminate the denominators, we find the least common multiple (LCM) of 66 and 88. The LCM of 66 and 88 is 2424.
  • Multiply the entire equation by 2424: 24(x6)+24(y8)=24×124 \left(\frac{x}{6}\right) + 24 \left(\frac{y}{8}\right) = 24 \times 1 4x+3y=244x + 3y = 24

Step 7: Check if the point (3,4) satisfies the equation and compare with given options.

  • Substitute x=3 and y=4 in the equation 4x+3y=24
  • 4(3) + 3(4) = 12 + 12 = 24. Hence the point satisfies the equation.
  • The equation matches option (C).

Common Mistakes & Tips

  • Intercept Form: Recognizing when to use the intercept form is crucial. Look for keywords like "intercepts" or "cuts the axes."
  • Midpoint Formula: Double-check that you're using the midpoint formula correctly and that you've assigned the coordinates correctly.
  • Verification: Always verify your final equation by substituting the given point to ensure it lies on the line.

Summary

This problem demonstrates how to combine the intercept form of a line with the midpoint formula. By recognizing that the given point bisects the intercept between the axes, we can use the midpoint formula to determine the x and y intercepts. Substituting these values back into the intercept form gives us the equation of the line. The final equation is 4x+3y=244x + 3y = 24, which corresponds to option (C).

The final answer is \boxed{4x + 3y = 24}, which corresponds to option (C).

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