Question
Let a variable line of slope passing through the point intersect the coordinate axes at the points and . The minimum value of the sum of the distances of and from the origin is
Options
Solution
Key Concepts and Formulas
- Equation of a Straight Line (Point-Slope Form): A line passing through the point with a slope can be represented as .
- Intercepts with Coordinate Axes: The x-intercept is the point where the line crosses the x-axis (where ), and the y-intercept is the point where the line crosses the y-axis (where ).
- AM-GM Inequality: For non-negative real numbers and , . Equality holds when .
Step-by-Step Solution
Step 1: Formulate the Equation of the Line and Determine Intercepts
First, we need to find the equation of the line and then determine the coordinates of points and where it intersects the axes.
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Equation of the Line: The line passes through the point and has a slope . Using the point-slope form, the equation of the line is: Explanation: This step translates the given information (a point and a slope) into an algebraic equation representing the line.
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Coordinates of Point A (x-intercept): Point lies on the x-axis, so its y-coordinate is . Substitute into the line's equation: Since , we can divide by : So, point is . Explanation: By setting , we find the x-coordinate where the line crosses the x-axis. Since , will always be positive, meaning is on the positive x-axis.
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Coordinates of Point B (y-intercept): Point lies on the y-axis, so its x-coordinate is . Substitute into the line's equation: So, point is . Explanation: By setting , we find the y-coordinate where the line crosses the y-axis. Since , is negative, making always negative. This means is on the negative y-axis.
Step 2: Express the Sum of Distances from the Origin in Terms of
We need to find the sum of the distances of and from the origin . Let this sum be .
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Distance OA: Since , is always positive.
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Distance OB: Since , is always negative. Therefore, its absolute value is its negation:
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Sum of Distances S(m): Explanation: Distances are always non-negative. We use the absolute value to ensure this. The expression for is now a function of the slope , which we need to minimize. The domain for is .
Step 3: Optimize the Function Using AM-GM Inequality
To find the minimum value of , we will use the AM-GM inequality on the terms and (since , both terms are positive).
The equality holds when , which gives .
Thus, the minimum value of is .
Explanation: AM-GM provides an elegant way to find the minimum of sums of positive terms, especially when their product is constant. It confirms the critical value of and the minimum value of the variable part of .
Step 4: Calculate the Minimum Value of
Substitute the optimal value of back into the expression for .
Therefore, the minimum value of the sum of the distances of and from the origin is .
Common Mistakes & Tips
- Absolute Values for Distances: Always remember that distances are non-negative.
- Domain of : The condition is crucial.
- AM-GM Applicability: Recognize when AM-GM can be used for quick optimization.
Summary
This problem demonstrates a classic application of coordinate geometry and the AM-GM inequality. The key steps involve: setting up the equation of the line, finding the x and y intercepts in terms of the slope , formulating the total distance function , and minimizing using the AM-GM inequality.
The minimum sum of distances is , which corresponds to option (D). The final answer is \boxed{25}.