Logarithm of Complex Numbers for JEE Main – Essential Guide
Complex logarithms appear occasionally in JEE Main, often yielding surprising results like $i^i$ being real. Mastering these formulas provides quick solutions to otherwise tricky problems.
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Logarithm of Complex Numbers for JEE Main – Essential Guide
Introduction
Complex logarithms appear occasionally in JEE Main, often yielding surprising results like ii being real. Mastering these formulas provides quick solutions to otherwise tricky problems.
The Core Formula (Memorize This!)
For z=x+iy=0:
log(z)=ln∣z∣+iarg(z)
Where:
∣z∣=x2+y2 (modulus)
arg(z) = angle in radians (principal value: −π<θ≤π)
Principal Value: The value when arg(z) is taken in (−π,π].
Essential Examples (JEE Favorites)
1. log(i)
i=eiπ/2 ⇒ log(i)=0+i⋅2π=2iπ
2. log(−1)
−1=eiπ ⇒ log(−1)=0+iπ=iπ
3. log(1+i)
1+i=2eiπ/4 ⇒ log(1+i)=21ln2+4iπ
The ii Surprise – A Real Number!
ii=eilog(i)=ei⋅2iπ=e−π/2≈0.2079
Key Insight:ii is purely real despite having imaginary base and exponent!
General Power Formula
For complex z,w:
zw=ewlog(z)
Step-by-step:
Find log(z)=ln∣z∣+iarg(z)
Multiply by w: wlog(z)
Compute e(result) using Euler's formula if needed
JEE PYQs & Patterns Solved
PYQ 1: JEE Main 2019 Pattern
Find principal value of ii
30-second solution:log(i)=iπ/2ii=ei⋅iπ/2=e−π/2
Answer:e−π/2
PYQ 2: JEE Advanced Pattern
Find (−1)i
Solution:log(−1)=iπ(−1)i=ei⋅iπ=e−π
Answer:e−π (also real!)
PYQ 3: Value Determination
If log(x+iy)=a+ib, find a,b
Solution:log(x+iy)=lnx2+y2+itan−1(y/x)
So a=21ln(x2+y2),
b=tan−1(y/x) (with quadrant adjustment)
Quick Reference Table
z
log(z) (Principal Value)
1
0
−1
iπ
i
iπ/2
−i
−iπ/2
1+i
21ln2+iπ/4
3+i
ln2+iπ/6
2
ln2
Important Properties (with Caveats)
1. Product Rule (modulo 2πi)
log(z1z2)=log(z1)+log(z2)+2πik
2. Power Rule (for integer n)
log(zn)=nlog(z)+2πik
3. Conjugate Property
log(zˉ)=log(z)if arg(z)=π
Special Results Worth Memorizing
ii=e−π/2 ≈ 0.2079 (real)
(−1)i=e−π ≈ 0.0432 (real)
2i=cos(ln2)+isin(ln2) (on unit circle)
eiπ=−1 (Euler's identity)
Problem Types & Strategies
Type 1: Direct Evaluation
Example: Find log(1−i3)Strategy: Convert to polar form reiθ, then log(z)=lnr+iθ