Skip to main content
Back to Trigonometric Equations
JEE Main 2020
Trigonometric Equations
Trigonometric Equations
Medium

Question

Let S be the sum of all solutions (in radians) of the equation sin4θ+cos4θsinθcosθ=0{\sin ^4}\theta + {\cos ^4}\theta - \sin \theta \cos \theta = 0 in [0, 4π\pi]. Then 8Sπ{{8S} \over \pi } is equal to ____________.

Answer: 4

Solution

Given equation sin4θ+cos4θsinθcosθ=0{\sin ^4}\theta + {\cos ^4}\theta - \sin \theta \cos \theta = 0 1sin2θcos2θsinθcosθ=0 \Rightarrow 1 - {\sin ^2}\theta {\cos ^2}\theta - \sin \theta \cos \theta = 0 2(sin2θ)2sin2θ=0 \Rightarrow 2 - {(\sin 2\theta )^2} - \sin 2\theta = 0 (sin2θ)2+(sin2θ)2=0 \Rightarrow {(\sin 2\theta )^2} + (\sin 2\theta ) - 2 = 0 (sin2θ+2)(sin2θ1)=0 \Rightarrow (\sin 2\theta + 2)(\sin 2\theta - 1) = 0 sin2θ=1 \Rightarrow \sin 2\theta = 1 or sin2θ=2\sin 2\theta = - 2 (Not Possible) 2θ=π2,5π2,9π2,13π2 \Rightarrow 2\theta = {\pi \over 2},{{5\pi } \over 2},{{9\pi } \over 2},{{13\pi } \over 2} θ=π4,5π4,9π4,13π4 \Rightarrow \theta = {\pi \over 4},{{5\pi } \over 4},{{9\pi } \over 4},{{13\pi } \over 4} S=π4+5π4+9π4+13π4=7π\Rightarrow S = {\pi \over 4} + {{5\pi } \over 4} + {{9\pi } \over 4} + {{13\pi } \over 4} = 7\pi 8Sπ=8×7ππ=56.00 \Rightarrow {{8S} \over \pi } = {{8 \times 7\pi } \over \pi } = 56.00

Practice More Trigonometric Equations Questions

View All Questions