Given equation sin4θ+cos4θ−sinθcosθ=0 ⇒1−sin2θcos2θ−sinθcosθ=0 ⇒2−(sin2θ)2−sin2θ=0 ⇒(sin2θ)2+(sin2θ)−2=0 ⇒(sin2θ+2)(sin2θ−1)=0 ⇒sin2θ=1 or sin2θ=−2 (Not Possible) ⇒2θ=2π,25π,29π,213π ⇒θ=4π,45π,49π,413π ⇒S=4π+45π+49π+413π=7π ⇒π8S=π8×7π=56.00