Skip to main content
Back to Trigonometry
JEE Main 2021
Trigonometry
Trigonometric Ratio and Identites
Medium

Question

2sin(π22)sin(3π22)sin(5π22)sin(7π22)sin(9π22)2 \sin \left(\frac{\pi}{22}\right) \sin \left(\frac{3 \pi}{22}\right) \sin \left(\frac{5 \pi}{22}\right) \sin \left(\frac{7 \pi}{22}\right) \sin \left(\frac{9 \pi}{22}\right) is equal to :

Options

Solution

2sinπ22sin3π22sin5π22sin7π22sin9π222\sin {\pi \over {22}}\sin {{3\pi } \over {22}}\sin {{5\pi } \over {22}}\sin {{7\pi } \over {22}}\sin {{9\pi } \over {22}} =2sin(11π10π22)sin(11π8π22)sin(11π6π22)sin(11π4π22)sin(11π2π22) = 2\sin \left( {{{11\pi - 10\pi } \over {22}}} \right)\sin \left( {{{11\pi - 8\pi } \over {22}}} \right)\sin \left( {{{11\pi - 6\pi } \over {22}}} \right)\sin \left( {{{11\pi - 4\pi } \over {22}}} \right)\sin \left( {{{11\pi - 2\pi } \over {22}}} \right) =2cosπ11cos2π11cos3π11cos4π11cos5π11 = 2\cos {\pi \over {11}}\cos {{2\pi } \over {11}}\cos {{3\pi } \over {11}}\cos {{4\pi } \over {11}}\cos {{5\pi } \over {11}} =2sin32π1125sinπ11 = {{2\sin {{32\pi } \over {11}}} \over {{2^5}\sin {\pi \over {11}}}} =116 = {1 \over {16}}

Practice More Trigonometry Questions

View All Questions