f(θ)=3(sin4(23π−θ)+sin4(3x+θ))−2(1−sin22θ) S={θ∈[0,π]:f′(θ)=−23} ⇒f(θ)=3(cos4θ+sin4θ)−2cos22θ ⇒f(θ)=3(1−21sin22θ)−2cos22θ ⇒f(θ)=3−23sin22θ−2cos2θ =23−21cos22θ=23−21(21+cos4θ) f(θ)=45−4cos4θ f′(θ)=sin4θ ⇒f′(θ)=sin4θ=−23 ⇒4θ=nπ+(−1)n3π ⇒θ=4nπ+(−1)n12π