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JEE Main 2019
Trigonometry
Trigonometric Ratio and Identites
Easy

Question

The expression tanA1cotA+cotA1tanA{{\tan {\rm A}} \over {1 - \cot {\rm A}}} + {{\cot {\rm A}} \over {1 - \tan {\rm A}}} can be written as:

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Solution

Given expression can be written as sinAcosA×sinAsinAcosA+cosAsinA×cosAcosAsinA{{\sin A} \over {\cos A}} \times {{sin\,A} \over {\sin A - \cos A}} + {{\cos A} \over {\sin A}} \times {{\cos A} \over {\cos A - sin\,A}} (As tanA=sinAcosA\tan A = {{\sin A} \over {\cos A}} and cotA=cosAsinA\cot A = {{\cos A} \over {\sin A}} ) =1sinAcosA{sin3Acos3AcosAsinA} = {1 \over {\sin A - \cos A}}\left\{ {{{{{\sin }^3}A - {{\cos }^3}A} \over {\cos A\sin A}}} \right\} =sin2A+sinAcosA+cos2AsinAcosA = {{{{\sin }^2}A + \sin A\cos A + {{\cos }^2}\,A} \over {\sin A\cos A}} =1+secAcosecA = 1 + \sec\, A{\mathop{\rm cosec}\nolimits} \,A

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