JEE Main 2023
Trigonometry
Trigonometric Ratio and Identites
Easy
Question
The maximum value of 3cos + 5sin for any real value of is :
Options
Solution
y = 3cos + 5 sin + cos y max = =
The maximum value of 3cos + 5sin for any real value of is :
y = 3cos + 5 sin + cos y max = =