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JEE Main 2023
Trigonometry
Trigonometric Ratio and Identites
Easy

Question

The maximum value of 3cosθ\theta + 5sin (θπ6)\left( {\theta - {\pi \over 6}} \right) for any real value of θ\theta is :

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Solution

y = 3cosθ\theta + 5 (sinθ32cosθ12)\left( {\sin \theta {{\sqrt 3 } \over 2} - \cos \theta {1 \over 2}} \right) 532{{5\sqrt 3 } \over 2} sinθ\theta + 12{1 \over 2}cosθ\theta y max = 754+14\sqrt {{{75} \over 4} + {1 \over 4}} = 19\sqrt {19}

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