JEE Main 2020
Trigonometry
Trigonometric Ratio and Identites
Medium
Question
For any , the expression 3{(\cos \theta - \sin \theta )^4}$$$$ + 6{(\sin \theta + \cos \theta )^2} + 4{\sin ^6}\theta equals :
Options
Solution
Given, 3(sin cos) 4 + 6(sin + cos) 2 + 4sin 6 = 3[(sin cos) 2 ] 2 + 6 (sin 2 + cos 2 + 2sincos) + 4sin 6 = 3[sin 2 + cos 2 2sincos] 2 + 6(1 + sin2) + 4sin 6 = 3(1 sin2) 2 + 6(1 + sin2) + 4sin 6 = 3 (1 2 sin2 + sin 2 2) + 6 + 6sin2 + 4sin 6 = 3 6sin2 + 3sin 2 2 + 6 + 6sin2 + 4sin 6 = 9 + 3sin 2 2 + 4 sin 6 = 9 + 3(2sincos) 2 + 4(1 cos 2 ) 3 = 9 + 12sin 2 cos 2 + 4 (1 cos 6 3cos 2 + 3cos 4 ) = 13 + 12 (1 cos 2 4cos 6 12cos + 12 cos 4 = 13 + 12 cos 2 12 cos 4 4cos 6 12 cos 2 + 12 cos 4 = 13 4 cos 6