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JEE Main 2019
Trigonometry
Trigonometric Ratio and Identites
Easy

Question

The value of cos 2 10° – cos10°cos50° + cos 2 50° is

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Solution

cos 2 10° – cos10°cos50° + cos 2 50° = 12{1 \over 2}[ 2cos 2 10° – 2cos10°cos50° + 2cos 2 50°] = 12{1 \over 2}[ 1 + cos20° - cos60° - cos40° + 1 + cos100°] = 12{1 \over 2}[ 2 - 12{1 \over 2} + cos20° + cos100° - cos40°] = 12{1 \over 2}[ 32{3 \over 2} + 2cos60°cos40° - cos40°] = 12{1 \over 2}[ 32{3 \over 2} + cos40° - cos40°] = 34{3 \over 4}

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