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JEE Main 2023
Vector Algebra
Vector Algebra
Easy

Question

Let a=i^+j^k^\overrightarrow a = \widehat i + \widehat j - \widehat k and c=2i^3j^+2k^\overrightarrow c = 2\widehat i - 3\widehat j + 2\widehat k. Then the number of vectors b\overrightarrow b such that b×c=a\overrightarrow b \times \overrightarrow c = \overrightarrow a and b|\overrightarrow b | \in {1, 2, ........, 10} is :

Options

Solution

Key Concepts and Formulas

  • Geometric Interpretation of Cross Product: The cross product of two vectors, b×c\overrightarrow b \times \overrightarrow c, results in a vector that is perpendicular to both b\overrightarrow b and c\overrightarrow c.
  • Perpendicularity Condition: If a vector a\overrightarrow a is the result of a cross product b×c\overrightarrow b \times \overrightarrow c, then a\overrightarrow a must be perpendicular to c\overrightarrow c. This means their dot product is zero: ac=0\overrightarrow a \cdot \overrightarrow c = 0.
  • Dot Product Calculation: For vectors u=uxi^+uyj^+uzk^\overrightarrow u = u_x \widehat i + u_y \widehat j + u_z \widehat k and v=vxi^+vyj^+vzk^\overrightarrow v = v_x \widehat i + v_y \widehat j + v_z \widehat k, their dot product is uv=uxvx+uyvy+uzvz\overrightarrow u \cdot \overrightarrow v = u_x v_x + u_y v_y + u_z v_z.

Step-by-Step Solution

Step 1: Understand the Problem and Given Information We are given two vectors, a=i^+j^k^\overrightarrow a = \widehat i + \widehat j - \widehat k and c=2i^3j^+2k^\overrightarrow c = 2\widehat i - 3\widehat j + 2\widehat k. We need to find the number of vectors b\overrightarrow b that satisfy the equation b×c=a\overrightarrow b \times \overrightarrow c = \overrightarrow a, with the additional constraint that the magnitude of b\overrightarrow b, b|\overrightarrow b |, must be an integer between 1 and 10, inclusive.

Step 2: Apply the Geometric Property of the Cross Product The fundamental property of the cross product states that if a=b×c\overrightarrow a = \overrightarrow b \times \overrightarrow c, then the vector a\overrightarrow a must be perpendicular to both b\overrightarrow b and c\overrightarrow c. A necessary condition for the existence of such a vector b\overrightarrow b is that a\overrightarrow a must be perpendicular to c\overrightarrow c.

  • Why this step? This is a crucial first check. If a\overrightarrow a is not perpendicular to c\overrightarrow c, then no such vector b\overrightarrow b can exist, and we can immediately conclude that the number of solutions is zero, without needing to perform further calculations to find b\overrightarrow b.

Step 3: Check the Perpendicularity Condition using the Dot Product For a\overrightarrow a and c\overrightarrow c to be perpendicular, their dot product ac\overrightarrow a \cdot \overrightarrow c must be equal to zero. Let's calculate this dot product using the given vectors: a=1i^+1j^1k^\overrightarrow a = 1\widehat i + 1\widehat j - 1\widehat k c=2i^3j^+2k^\overrightarrow c = 2\widehat i - 3\widehat j + 2\widehat k ac=(1)(2)+(1)(3)+(1)(2)\overrightarrow a \cdot \overrightarrow c = (1)(2) + (1)(-3) + (-1)(2) ac=232\overrightarrow a \cdot \overrightarrow c = 2 - 3 - 2 ac=3\overrightarrow a \cdot \overrightarrow c = -3

Step 4: Analyze the Result of the Dot Product We found that ac=3\overrightarrow a \cdot \overrightarrow c = -3. According to the necessary condition established in Step 2, for a vector b\overrightarrow b to exist such that b×c=a\overrightarrow b \times \overrightarrow c = \overrightarrow a, it must be true that ac=0\overrightarrow a \cdot \overrightarrow c = 0.

  • Why this analysis? We are comparing the calculated dot product with the required condition. Since 30-3 \neq 0, the necessary condition for the existence of b\overrightarrow b is not satisfied. This means that the given vectors a\overrightarrow a and c\overrightarrow c are not perpendicular, and therefore, there is no vector b\overrightarrow b that can satisfy the equation b×c=a\overrightarrow b \times \overrightarrow c = \overrightarrow a.

Step 5: Conclude the Number of Vectors b\overrightarrow b Because the fundamental requirement for the existence of b\overrightarrow b is violated, no such vector b\overrightarrow b exists, regardless of its magnitude. Therefore, the number of vectors b\overrightarrow b satisfying the given conditions is 0. The constraint on b|\overrightarrow b | becomes irrelevant in this case.

Common Mistakes & Tips

  • Forgetting the Necessary Condition: A common mistake is to immediately try to find b\overrightarrow b without first checking if ac=0\overrightarrow a \cdot \overrightarrow c = 0. If this check is skipped, one might embark on a lengthy calculation that ultimately leads to a contradiction or no solution.
  • Confusing Magnitude and Vector Existence: The problem asks for the number of vectors b\overrightarrow b. If no vector b\overrightarrow b satisfies the primary vector equation, then the constraint on its magnitude is moot.
  • Understanding Scalar Triple Product: The expression c(b×c)\overrightarrow c \cdot (\overrightarrow b \times \overrightarrow c) is a scalar triple product. If you were to multiply both sides of b×c=a\overrightarrow b \times \overrightarrow c = \overrightarrow a by c\overrightarrow c using a dot product, you would get c(b×c)=ca\overrightarrow c \cdot (\overrightarrow b \times \overrightarrow c) = \overrightarrow c \cdot \overrightarrow a. Since c(b×c)=0\overrightarrow c \cdot (\overrightarrow b \times \overrightarrow c) = 0 (as b×c\overrightarrow b \times \overrightarrow c is perpendicular to c\overrightarrow c), this immediately leads to ca=0\overrightarrow c \cdot \overrightarrow a = 0, which is the same condition we derived from the geometric interpretation.

Summary

The problem requires finding the number of vectors b\overrightarrow b satisfying b×c=a\overrightarrow b \times \overrightarrow c = \overrightarrow a and a condition on b|\overrightarrow b|. The key insight is that for such an equation to hold, the resultant vector a\overrightarrow a must be perpendicular to the vector c\overrightarrow c. We tested this condition by calculating the dot product ac\overrightarrow a \cdot \overrightarrow c. Since ac=30\overrightarrow a \cdot \overrightarrow c = -3 \neq 0, the necessary perpendicularity condition is not met. Consequently, no vector b\overrightarrow b can exist that satisfies the given cross product equation. Therefore, the number of such vectors is zero.

The final answer is 0\boxed{0} which corresponds to option (A).

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