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JEE Main 2018
Complex Numbers
Complex Numbers
Easy

Question

The equation |z – i| = |z – 1|, i = 1\sqrt { - 1} , represents :

Options

Solution

Key Concepts and Formulas

  • Modulus of a Complex Number: For a complex number z=x+iyz = x + iy, the modulus is given by z=x2+y2|z| = \sqrt{x^2 + y^2}, which represents the distance of the point (x,y)(x, y) from the origin in the complex plane.
  • Geometric Interpretation of Modulus: z1z2|z_1 - z_2| represents the distance between the points corresponding to the complex numbers z1z_1 and z2z_2 in the complex plane.
  • Perpendicular Bisector: The locus of a point equidistant from two fixed points is the perpendicular bisector of the line segment joining the two fixed points.

Step-by-Step Solution

Step 1: Represent the complex number z in Cartesian form Let z=x+iyz = x + iy, where xx and yy are real numbers. This allows us to work with real coordinates in the complex plane. z=x+iyz = x + iy

Step 2: Substitute z into the given equation Substitute z=x+iyz = x + iy into the equation zi=z1|z - i| = |z - 1|: x+iyi=x+iy1|x + iy - i| = |x + iy - 1| This replaces the complex variable zz with its real and imaginary components.

Step 3: Group the real and imaginary parts Group the real and imaginary terms within the modulus: x+i(y1)=(x1)+iy|x + i(y - 1)| = |(x - 1) + iy| This step prepares the expressions for applying the modulus formula.

Step 4: Apply the modulus formula Apply the modulus formula a+ib=a2+b2|a + ib| = \sqrt{a^2 + b^2} to both sides: x2+(y1)2=(x1)2+y2\sqrt{x^2 + (y - 1)^2} = \sqrt{(x - 1)^2 + y^2} This converts the complex equation into a real equation involving square roots.

Step 5: Square both sides Square both sides of the equation to eliminate the square roots: x2+(y1)2=(x1)2+y2x^2 + (y - 1)^2 = (x - 1)^2 + y^2 This simplifies the equation and removes the square roots.

Step 6: Expand and simplify Expand the squared terms: x2+y22y+1=x22x+1+y2x^2 + y^2 - 2y + 1 = x^2 - 2x + 1 + y^2 Now, simplify by cancelling out common terms on both sides (x2x^2, y2y^2, and 1): 2y=2x-2y = -2x

Step 7: Solve for y Divide both sides by -2 to find the relationship between xx and yy: y=xy = x This is the equation of the locus.

Step 8: Interpret the equation The equation y=xy = x represents a straight line passing through the origin (0, 0) with a slope of 1.

Common Mistakes & Tips

  • Sign Errors: Be extremely careful with signs when grouping real and imaginary terms, and when expanding squared terms.
  • Geometric Intuition: Always try to visualize the problem geometrically. The equation za=zb|z - a| = |z - b| always represents the perpendicular bisector of the line segment joining the points representing aa and bb.
  • Modulus Formula: Ensure you apply the modulus formula correctly.

Summary

The equation zi=z1|z - i| = |z - 1| represents the locus of points equidistant from the complex numbers ii and 11 in the complex plane. By substituting z=x+iyz = x + iy and simplifying, we find the equation of the locus to be y=xy = x, which is a straight line passing through the origin with a slope of 1. This corresponds to option (D).

Final Answer The final answer is \boxed{D}, which corresponds to option (D).

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