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JEE Main 2018
Complex Numbers
Complex Numbers
Medium

Question

The locus of the centre of a circle which touches the circle zz1=a\left| {z - {z_1}} \right| = a andzz2=b\left| {z - {z_2}} \right| = b\, externally (z,z1&z2z,\,{z_1}\,\& \,{z_2}\, are complex numbers) will be :

Options

Solution

Key Concepts and Formulas

  • Equation of a Circle in the Complex Plane: A circle with center z0z_0 and radius RR is given by zz0=R|z - z_0| = R.
  • Condition for External Tangency: Two circles with centers z1,z2z_1, z_2 and radii r1,r2r_1, r_2 touch externally if z1z2=r1+r2|z_1 - z_2| = r_1 + r_2.
  • Definition of an Ellipse: An ellipse is the locus of a point such that the sum of its distances from two fixed points (foci) is constant: zz1+zz2=constant|z - z_1| + |z - z_2| = \text{constant}.

Step-by-Step Solution

Step 1: Define the given circles and the variable circle.

  • Why this step? We need to clearly define the circles given in the problem to set up the equations for their tangency.
  • Let C1C_1 be the circle zz1=a|z - z_1| = a with center z1z_1 and radius aa.
  • Let C2C_2 be the circle zz2=b|z - z_2| = b with center z2z_2 and radius bb.
  • Let C3C_3 be the variable circle with center z3z_3 (whose locus we seek) and radius rr.

Step 2: Apply the external tangency condition between C3C_3 and C1C_1.

  • Why this step? The problem states that C3C_3 touches C1C_1 externally. This geometric condition translates to an algebraic equation.
  • The distance between the centers of C3C_3 and C1C_1 is the sum of their radii: z3z1=r+a(Equation 1)|z_3 - z_1| = r + a \quad \text{(Equation 1)}

Step 3: Apply the external tangency condition between C3C_3 and C2C_2.

  • Why this step? Similarly, C3C_3 touches C2C_2 externally. This gives us another equation relating z3z_3 and rr.
  • The distance between the centers of C3C_3 and C2C_2 is the sum of their radii: z3z2=r+b(Equation 2)|z_3 - z_2| = r + b \quad \text{(Equation 2)}

Step 4: Eliminate the variable radius rr.

  • Why this step? We want an equation involving only z3z_3, z1z_1, z2z_2, aa, and bb to describe the locus of z3z_3. The radius rr is not constant and must be eliminated.
  • From Equation 1, we have r=z3z1ar = |z_3 - z_1| - a.
  • Substitute this into Equation 2: z3z2=(z3z1a)+b|z_3 - z_2| = (|z_3 - z_1| - a) + b

Step 5: Rearrange the equation to identify the locus.

  • Why this step? We want to rearrange the equation to match the standard form of a conic section.
  • Rearranging the terms, we get: z3z1+z3z2=a+b|z_3 - z_1| + |z_3 - z_2| = a + b

Step 6: Recognize the locus as an ellipse.

  • Why this step? We need to recognize the geometric shape represented by the equation.
  • The equation z3z1+z3z2=a+b|z_3 - z_1| + |z_3 - z_2| = a + b represents the locus of a point z3z_3 such that the sum of its distances from two fixed points z1z_1 and z2z_2 is a constant a+ba+b. This is the definition of an ellipse with foci at z1z_1 and z2z_2.

Common Mistakes & Tips

  • Confusion between Ellipse and Hyperbola: Ensure you remember the definitions of both. Ellipses involve the sum of distances, while hyperbolas involve the difference.
  • Incorrect Tangency Conditions: Double-check whether the circles touch externally or internally. The conditions are different, leading to different loci.
  • Not Eliminating the Variable Radius: For locus problems, make sure to eliminate any variable parameters that are not part of the final locus equation.

Summary

By applying the condition for external tangency to the given circles and eliminating the variable radius of the moving circle, we arrive at the equation z3z1+z3z2=a+b|z_3 - z_1| + |z_3 - z_2| = a + b. This equation represents an ellipse with foci at z1z_1 and z2z_2.

The final answer is \boxed{an ellipse}, which corresponds to option (A).

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