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JEE Main 2020
Conic Sections
Hyperbola
Hard

Question

If the equation of the hyperbola with foci (4,2)(4,2) and (8,2)(8,2) is 3x2y2αx+βy+γ=03 x^2-y^2-\alpha x+\beta y+\gamma=0, then α+β+γ\alpha+\beta+\gamma is equal to__________.

Answer: 6

Solution

This problem asks us to find the sum of coefficients α+β+γ\alpha+\beta+\gamma for a given hyperbola equation, using information about its foci. We will systematically use the properties of hyperbolas and algebraic manipulation to solve this.

1. Determine the Hyperbola's Center and Orientation

The first crucial step in analyzing any conic section, especially when given its foci, is to determine its center and the orientation of its transverse axis.

  • Key Concept: The center of a hyperbola is the midpoint of the segment connecting its two foci.
  • Why this step? The center (h,k)(h,k) is a fundamental parameter in the standard equation of a hyperbola. Its coordinates are directly related to the coefficients α\alpha and β\beta in the given general

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