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Conic Sections
Ellipse
Hard

Question

If the midpoint of a chord of the ellipse x29+y24=1\frac{x^2}{9}+\frac{y^2}{4}=1 is (2,4/3)(\sqrt{2}, 4 / 3), and the length of the chord is 2α3\frac{2 \sqrt{\alpha}}{3}, then α\alpha is :

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Solution

1. Understanding the Problem and Identifying Key Information

We are given an ellipse and the coordinates of the midpoint of one of its chords. Our goal is to determine a specific parameter α\alpha related to the length of this chord.

  • Equation of the Ellipse: The given ellipse is x29+y24=1\frac{x^2}{9}+\frac{y^2}{4}=1.
    • By comparing this to the standard form x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1, we can identify the semi-major axis squared a2=9a^2=9 (so a=3a=3) and the semi-minor axis squared b2=4b^2=4 (so b=2b=2).

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