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JEE Main 2023
Conic Sections
Parabola
Medium

Question

If the equation of the parabola, whose vertex is at (5, 4) and the directrix is 3x+y29=03x + y - 29 = 0, is x2+ay2+bxy+cx+dy+k=0{x^2} + a{y^2} + bxy + cx + dy + k = 0, then a+b+c+d+ka + b + c + d + k is equal to :

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Solution

1. Fundamental Definition of a Parabola

A parabola is defined as the locus of all points P(x,y)P(x, y) in a plane such that its distance from a fixed point, called the focus (SS), is equal to its perpendicular distance from a fixed line, called the directrix (LL). Mathematically, this definition is expressed as PS=PMPS = PM, where MM is the foot of the perpendicular from PP to the directrix. Squaring both sides, we get PS2=PM2PS^2 = PM^2, which helps in deriving the algebraic equation of the parabola.

2. Identifying Key Elements: Vertex, Directrix, and Focus

We are given:

  • Vertex (VV): $(5

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