cosec(2cot−1(5)+cos−1(54)) cosec(2tan−1(51)+cos−1(54)) =cosec(tan−1(1−(51)22(51))+cos−1(54)) =cosec(tan−1(125)+cos−1(54)) Let tan−1(5/12)=θ⇒sinθ=135,cosθ=1312 and cos−1(54)=ϕ⇒cosϕ=54 and sinϕ=53 =cosec(θ+ϕ) =sinθcosϕ+cosθsinϕ1 =135.54+1312.531=5665