cot−1(α)=cot−12+cot−18+cot−118+cot−132+....100 terms =tan−121+tan−181+tan−1181+tan−1321+....100 term =k=1∑100tan−12k21 =k=1∑100tan−14k22=k=1∑ntan−11+(2k−1)(2k+1)(2k+1)−(2k−1) =k=1∑100(tan−1(2k+1)−tan−1(2k−1)) =tan−1201−tan−11 =tan−1202200 =cot−1(1.01) Hence α=1.01