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JEE Main 2020
Inverse Trigonometric Functions
Inverse Trigonometric Functions
Hard

Question

The domain of the function f(x)=sin1(x23x+2x2+2x+7)f(x)=\sin ^{-1}\left(\frac{x^{2}-3 x+2}{x^{2}+2 x+7}\right) is :

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Solution

f(x)=sin1(x23x+2x2+2x+7)f(x)=\sin ^{-1}\left(\frac{x^{2}-3 x+2}{x^{2}+2 x+7}\right) 1x23x+2x2+2x+71-1 \leq \frac{x^{2}-3 x+2}{x^{2}+2 x+7} \leq 1 x23x+2x2+2x+71x23x+2x2+2x+75x5x1\begin{aligned} & \frac{x^{2}-3 x+2}{x^{2}+2 x+7} \leq 1 \\\\ & x^{2}-3 x+2 \leq x^{2}+2 x+7 \\\\ & 5 x \geq-5 \\\\ & x \geq-1 \end{aligned} And x23x+2x2+2x+71\frac{x^{2}-3 x+2}{x^{2}+2 x+7} \geq-1 x23x+2x22x7x^{2}-3 x+2 \geq-x^{2}-2 x-7 2x2x+902 x^{2}-x+9 \geq 0 xRx \in R (i) \cap (ii) Domain [1,)\in[-1, \infty)

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