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JEE Main 2019
Mathematical Reasoning
Mathematical Reasoning
Easy

Question

If p \to (\sim p\vee \sim q) is false, then the truth values of p and q are respectively :

Options

Solution

Key Concepts and Formulas

  • Conditional Statement (pqp \to q): The statement "pqp \to q" (read as "if p, then q" or "p implies q") is false only when pp is true and qq is false. Otherwise, it is true.
  • Negation (p\sim p): The negation of a statement pp (denoted by p\sim p) is true when pp is false, and false when pp is true.
  • Disjunction (pqp \vee q): The disjunction of two statements pp and qq (denoted by pqp \vee q, read as "p or q") is true if at least one of pp or qq is true. It is false only when both pp and qq are false.

Step-by-Step Solution

Step 1: Analyze the given condition.

The given condition is that the statement p(pq)p \to (\sim p \vee \sim q) is false. We need to find the truth values of pp and qq that make this statement false.

Step 2: Apply the definition of conditional statement.

A conditional statement prp \to r is false only when pp is true and rr is false. In our case, rr is (pq)(\sim p \vee \sim q). Therefore, for p(pq)p \to (\sim p \vee \sim q) to be false, we must have: p is True and (pq) is Falsep \text{ is True and } (\sim p \vee \sim q) \text{ is False}

Step 3: Determine the truth value of p.

From Step 2, we know that pp must be true. p=Tp = T

Step 4: Determine the truth value of pq\sim p \vee \sim q.

From Step 2, we also know that pq\sim p \vee \sim q must be false. pq=F \sim p \vee \sim q = F

Step 5: Apply the definition of disjunction.

A disjunction aba \vee b is false only when both aa and bb are false. Therefore, for pq\sim p \vee \sim q to be false, we must have: p=F and q=F \sim p = F \text{ and } \sim q = F

Step 6: Determine the truth value of p from ~p = F.

Since p=F\sim p = F, it means that pp must be true. This is consistent with what we found in Step 3. p=Tp = T

Step 7: Determine the truth value of q from ~q = F.

Since q=F\sim q = F, it means that qq must be true. q=Tq = T

Step 8: Re-examine the problem statement and provided answer.

The problem statement asks for the truth values of pp and qq if p(pq)p \to (\sim p \vee \sim q) is false. We have determined that p=Tp = T and q=Tq = T.

Wait! The provided answer is (A) F, F. There must be an error in my reasoning or in the provided answer. Let's re-examine the truth table.

pq~p~q~p v ~qp -> (~p v ~q)
TTFFFF
TFFTTT
FTTFTT
FFTTTT

The truth table confirms that p(pq)p \to (\sim p \vee \sim q) is false only when pp is true and qq is true.

However, the given answer is (A) F, F. If we plug in F, F into the expression, we get: p = F, q = F ~p = T, ~q = T ~p v ~q = T v T = T p -> (~p v ~q) = F -> T = T So, the expression is TRUE, not FALSE.

There is an error in the provided answer. The correct answer should be T, T. I believe there is a typo in the options and option (A) should be T, T instead of F, F.

Step 9: Correct the error

The given options are incorrect. The correct option should be T, T.

Common Mistakes & Tips

  • Carefully consider all possible truth values when analyzing logical statements.
  • When a conditional statement is false, the antecedent is true and the consequent is false.
  • Always double-check your truth tables and logical deductions.

Summary

We analyzed the given conditional statement and determined the truth values of pp and qq that make the statement false. We found that pp and qq must both be true. However, the given answer is (A) F, F, which is incorrect. The correct answer should be T, T, implying an error in the provided options.

Final Answer

The final answer is \boxed{T, T}. This corresponds to a corrected option (A) which should read "T, T".

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