JEE Main 2020
Matrices & Determinants
Matrices and Determinants
Medium
Question
If = \left| {\matrix{ {x - 2} & {2x - 3} & {3x - 4} \cr {2x - 3} & {3x - 4} & {4x - 5} \cr {3x - 5} & {5x - 8} & {10x - 17} \cr } } \right| = Ax 3 + Bx 2 + Cx + D, then B + C is equal to :
Options
Solution
Key Concepts and Properties Used:
This problem involves evaluating a determinant and then extracting coefficients from the resulting polynomial. The key concepts and properties we will utilize are:
- Determinant Properties:
- Row/Column Operations: The value of a determinant remains unchanged if we apply the operation (or ). This is crucial for simplifying the determinant by creating zeros or common factors.
- Factoring out Common Elements: If all elements of a row or column are multiplied by a constant , then the value of the determinant is multiplied by . Conversely, a common factor from any row or column can be taken out of the determinant.
- Expansion of a Determinant: A determinant can be expanded along any row or column. The expansion along a row is given by , where is the cofactor of the element , and is the minor (determinant of the submatrix obtained by deleting row and column ). Expanding along a row/column with more zeros simplifies the calculation significantly.
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