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JEE Main 2020
Matrices & Determinants
Matrices and Determinants
Medium

Question

If Δ\Delta = \left| {\matrix{ {x - 2} & {2x - 3} & {3x - 4} \cr {2x - 3} & {3x - 4} & {4x - 5} \cr {3x - 5} & {5x - 8} & {10x - 17} \cr } } \right| = Ax 3 + Bx 2 + Cx + D, then B + C is equal to :

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Solution

Key Concepts and Properties Used:

This problem involves evaluating a 3×33 \times 3 determinant and then extracting coefficients from the resulting polynomial. The key concepts and properties we will utilize are:

  1. Determinant Properties:
    • Row/Column Operations: The value of a determinant remains unchanged if we apply the operation RiRi+kRjR_i \to R_i + kR_j (or CiCi+kCjC_i \to C_i + kC_j). This is crucial for simplifying the determinant by creating zeros or common factors.
    • Factoring out Common Elements: If all elements of a row or column are multiplied by a constant kk, then the value of the determinant is multiplied by kk. Conversely, a common factor from any row or column can be taken out of the determinant.
    • Expansion of a Determinant: A 3×33 \times 3 determinant can be expanded along any row or column. The expansion along a row ii is given by j=13aijCij\sum_{j=1}^{3} a_{ij} C_{ij}, where Cij=(1)i+jMijC_{ij} = (-1)^{i+j} M_{ij} is the cofactor of the element aija_{ij}, and MijM_{ij} is the minor (determinant of the submatrix obtained by deleting row ii and column jj). Expanding along a row/column with more zeros simplifies the calculation significantly.

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