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Properties of Triangle
Properties of Triangle
Easy

Question

In a triangle ABCABC, let C=π2\angle C = {\pi \over 2}. If rr is the inradius and RR is the circumradius of the triangle ABCABC, then 2(r+R)2(r+R) equals :

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Solution

We know by sin c rule csinC=2Rc=2RsinC{c \over {\sin C}} = 2R \Rightarrow c = 2R\sin C c=2R \Rightarrow c = 2R (\left( \, \right.as C=90\,\,\,\angle C = {90^ \circ } )\left. \, \right) Also tanC2=rsc\tan {C \over 2} = {r \over {s - c}} tanπ4=rsc \Rightarrow \tan {\pi \over 4} = {r \over {s - c}} (\left( \, \right.as C=90\,\,\,\angle C = {90^ \circ } )\left. \, \right) r=sc=a+bc2 \Rightarrow r = s - c = {{a + b - c} \over 2} 2r+c=a+b \Rightarrow 2r + c = a + b 2r+2R=a+b \Rightarrow 2r + 2R = a + b (using c=2Rc=2R)

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