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JEE Main 2020
Straight Lines
Straight Lines and Pair of Straight Lines
Easy

Question

If the sum of the slopes of the lines given by x22cxy7y2=0{x^2} - 2cxy - 7{y^2} = 0 is four times their product cc has the value :

Options

Solution

Key Concepts and Formulas

  • Homogeneous Equation of Second Degree: An equation of the form ax2+2hxy+by2=0ax^2 + 2hxy + by^2 = 0 represents a pair of straight lines passing through the origin.
  • Sum of Slopes: If m1m_1 and m2m_2 are the slopes of the lines represented by ax2+2hxy+by2=0ax^2 + 2hxy + by^2 = 0, then m1+m2=2hbm_1 + m_2 = -\frac{2h}{b}.
  • Product of Slopes: If m1m_1 and m2m_2 are the slopes of the lines represented by ax2+2hxy+by2=0ax^2 + 2hxy + by^2 = 0, then m1m2=abm_1 m_2 = \frac{a}{b}.

Step-by-Step Solution

Step 1: Identify the coefficients from the given equation. The given equation is x22cxy7y2=0x^2 - 2cxy - 7y^2 = 0. We need to compare this with the general form ax2+2hxy+by2=0ax^2 + 2hxy + by^2 = 0 to find the values of aa, hh, and bb.

  • a=1a = 1 (coefficient of x2x^2)
  • 2h=2c2h = -2c, so h=ch = -c (coefficient of xyxy)
  • b=7b = -7 (coefficient of y2y^2)

Step 2: Calculate the sum of the slopes (m1+m2m_1 + m_2). We use the formula m1+m2=2hbm_1 + m_2 = -\frac{2h}{b}. Substituting the values of hh and bb from Step 1: m1+m2=2(c)7=2c7m_1 + m_2 = -\frac{2(-c)}{-7} = -\frac{2c}{7}

Step 3: Calculate the product of the slopes (m1m2m_1 m_2). We use the formula m1m2=abm_1 m_2 = \frac{a}{b}. Substituting the values of aa and bb from Step 1: m1m2=17=17m_1 m_2 = \frac{1}{-7} = -\frac{1}{7}

Step 4: Apply the given condition. The problem states that the sum of the slopes is four times their product. This means: m1+m2=4(m1m2)m_1 + m_2 = 4(m_1 m_2) Substituting the expressions we found in Steps 2 and 3: 2c7=4(17)-\frac{2c}{7} = 4\left(-\frac{1}{7}\right)

Step 5: Solve for cc. We now have an equation with only cc as the unknown. We need to solve for cc: 2c7=47-\frac{2c}{7} = -\frac{4}{7} Multiply both sides by 7 to eliminate the fractions: 2c=4-2c = -4 Divide both sides by -2 to isolate cc: c=42=2c = \frac{-4}{-2} = 2

Common Mistakes & Tips

  • Sign Errors: Be extremely careful with signs, especially when identifying hh from 2h2h and when applying the formulas for the sum and product of slopes. A single sign error can lead to an incorrect answer.
  • Coefficient Identification: Make sure you correctly identify the coefficients aa, hh, and bb by comparing the given equation with the general form.
  • Formula Application: Double-check that you are using the correct formulas for the sum and product of slopes.

Summary

We identified the coefficients from the given equation, calculated the sum and product of the slopes using the standard formulas, and applied the given condition that the sum of the slopes is four times their product. Solving the resulting equation for cc gave us c=2c=2.

Final Answer The final answer is \boxed{2}, which corresponds to option (C).

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