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JEE Main 2020
Straight Lines
Straight Lines and Pair of Straight Lines
Easy

Question

If the system of linear equations x – 2y + kz = 1 2x + y + z = 2 3x – y – kz = 3 has a solution (x,y,z), z \ne 0, then (x,y) lies on the straight line whose equation is :

Options

Solution

Key Concepts and Formulas

  • System of Linear Equations: A set of linear equations with the same variables. The solution to the system is the set of values for the variables that satisfy all equations simultaneously.
  • Elimination Method: A method for solving systems of linear equations by adding or subtracting multiples of the equations to eliminate one or more variables.
  • Equation of a Straight Line: The general form of a straight line is Ax+By+C=0Ax + By + C = 0, where AA, BB, and CC are constants.

Step-by-Step Solution

Step 1: State the given system of equations. We are given the following system of linear equations: x2y+kz=1...(1)x - 2y + kz = 1 \quad \text{...(1)} 2x+y+z=2...(2)2x + y + z = 2 \quad \text{...(2)} 3xykz=3...(3)3x - y - kz = 3 \quad \text{...(3)} Our goal is to find the relationship between xx and yy by eliminating zz and kk.

Step 2: Eliminate kzkz by adding equations (1) and (3). Observe that equation (1) has a +kz+kz term and equation (3) has a kz-kz term. Adding these equations will eliminate both kk and zz from these terms simultaneously. Adding equation (1) and equation (3): (x2y+kz)+(3xykz)=1+3(x - 2y + kz) + (3x - y - kz) = 1 + 3

Step 3: Simplify the resulting equation. Combine like terms: (x+3x)+(2yy)+(kzkz)=4(x + 3x) + (-2y - y) + (kz - kz) = 4 4x3y=44x - 3y = 4

Step 4: Rewrite the equation in the standard form of a linear equation. Subtract 4 from both sides to get the equation in the form Ax+By+C=0Ax + By + C = 0: 4x3y4=04x - 3y - 4 = 0 This is the equation of the straight line on which the point (x,y)(x, y) lies.

Common Mistakes & Tips

  • Strategic Elimination: Look for opportunities to eliminate variables directly by adding or subtracting equations. In this case, the +kz+kz and kz-kz terms made elimination straightforward.
  • Avoid Unnecessary Calculations: Do not attempt to solve for x,y,z,x, y, z, and kk individually unless required. This problem only asks for a relationship between xx and yy, so finding a direct relationship is more efficient.
  • The Condition z0z \ne 0: The condition z0z \ne 0 is given to ensure that a solution exists with zz not equal to zero. However, this condition does not affect the elimination process to find the relationship between xx and yy.

Summary

By adding equations (1) and (3), we eliminated zz and kk simultaneously, resulting in the equation 4x3y=44x - 3y = 4, which can be rewritten as 4x3y4=04x - 3y - 4 = 0. This is the equation of the straight line on which the point (x,y)(x, y) must lie.

Final Answer

The final answer is \boxed{4x – 3y – 4 = 0}, which corresponds to option (A).

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