JEE Main 2021Trigonometric EquationsTrigonometric EquationsMediumQuestion The number of solutions of the equation 2x+3tanx=π,x∈[−2π,2π]−{±π2,±3π2} is: \text { The number of solutions of the equation } 2 x+3 \tan x=\pi, x \in[-2 \pi, 2 \pi]-\left\{ \pm \frac{\pi}{2}, \pm \frac{3 \pi}{2}\right\} \text { is: } The number of solutions of the equation 2x+3tanx=π,x∈[−2π,2π]−{±2π,±23π} is: OptionsA4B5C3D6Check AnswerHide SolutionSolution2x+3tanx=π⇒tanx=π−2x3,x∈[−2π,2π]−{±π2,±3π2}\begin{aligned} & 2 x+3 \tan x=\pi \\ & \Rightarrow \quad \tan x=\frac{\pi-2 x}{3}, x \in[-2 \pi, 2 \pi]-\left\{ \pm \frac{\pi}{2}, \pm \frac{3 \pi}{2}\right\} \end{aligned}2x+3tanx=π⇒tanx=3π−2x,x∈[−2π,2π]−{±2π,±23π} 5 solutions