Let S={sin22θ:(sin4θ+cos4θ)x2+(sin2θ)x+(sin6θ+cos6θ)=0 has real roots }. If α and β be the smallest and largest elements of the set S, respectively, then 3((α−2)2+(β−1)2) equals __________.
Answer: 0
Solution
For real roots D≥0sin22θ≥4(sin4θ+cos4θ)(sin6θ+cos6θ) Put sin22θ=t⇒t≥4(1−2t)(1−43t)2t≥(2−t)(4−3t)3t2−12t+8≤0t2−4t+38≤0(t−2)2+38−4≤0(t−2)2≤34−32≤t−2≤322−32≤t≤2+32∵t∈[0,1]⇒2−32≤t≤1α=2−32,β=1⇒3[(α−2)2+(β−1)2]=4