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JEE Main 2018
Trigonometric Equations
Trigonometric Equations
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Question

The number of solutions of cosx=sinx|\cos x|=\sin x, such that 4πx4π-4 \pi \leq x \leq 4 \pi is :

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Solution

Period of cosx=π|\cos x| = \pi And period of sinx=2π\sin x = 2\pi Graph of sinx\sin x and cosx|\cos x| cuts each other at two points A and B in [0,2π]\left[ {0,2\pi } \right] So, in [4π,4π]\left[ { - 4\pi ,4\pi } \right], total 4 similar graph will be present and graph of sinx\sin x and cosx|\cos x| will cut 4×2=84 \times 2 = 8 times. \therefore Total possible solutions = 8.

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