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JEE Main 2019
Trigonometry
Trigonometric Ratio and Identites
Hard

Question

If the equation cos 4 θ\theta + sin 4 θ\theta + λ\lambda = 0 has real solutions for θ\theta , then λ\lambda lies in the interval :

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Solution

cos 4 θ\theta + sin 4 θ\theta + λ\lambda = 0 \Rightarrow 1 – 2sin 2 θ\theta cos 2 θ\theta = -λ\lambda \Rightarrow 1 - 12×4\frac{1}{2} \times 4sin 2 θ\theta cos 2 θ\theta = -λ\lambda \Rightarrow 1 - sin22θ2\frac{\sin^{2} 2\theta }{2} = -λ\lambda \Rightarrow2(λ\lambda + 1) = sin 2 2θ\theta 0 \le 2 (λ\lambda + 1) \le 1 0 \le (λ\lambda + 1) \le 12\frac{1}{2} -1 \le λ\lambda \le -12\frac{1}{2}

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If the equation cos 4 + sin 4 + = 0 has real solutions for ,... | JEE Main 2019 Trigonometry | JEE Main - Mathematicon