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JEE Main 2023
Trigonometric Equations
Trigonometric Equations
Medium

Question

Let cosθcos(60θ)cos(60+θ)18,θϵ[0,2π]|\cos \theta \cos (60-\theta) \cos (60+\theta)| \leq \frac{1}{8}, \theta \epsilon[0,2 \pi]. Then, the sum of all θ[0,2π]\theta \in[0,2 \pi], where cos3θ\cos 3 \theta attains its maximum value, is :

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Solution

cosθcos(60θ)cos(60+θ)1814cos3θ18cos3θ is max if cos3θ=12θ=π9,5π9,7π9,11π9,13π9,17π9θi=6π\begin{aligned} & |\cos \theta \cos (60-\theta) \cos (60+\theta)| \leq \frac{1}{8} \\ & \Rightarrow \frac{1}{4}|\cos 3 \theta| \leq \frac{1}{8} \\ & \cos 3 \theta \text { is max if } \cos 3 \theta=\frac{1}{2} \\ & \therefore \theta=\frac{\pi}{9}, \frac{5 \pi}{9}, \frac{7 \pi}{9}, \frac{11 \pi}{9}, \frac{13 \pi}{9}, \frac{17 \pi}{9} \\ & \sum \theta_i=6 \pi \end{aligned}

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