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JEE Main 2021
Vector Algebra
Vector Algebra
Easy

Question

If the vectors AB=3i^+4k^\overrightarrow {AB} = 3\widehat i + 4\widehat k and AC=5i^2j^+4k^\overrightarrow {AC} = 5\widehat i - 2\widehat j + 4\widehat k are the sides of a triangle ABC,ABC, then the length of the median through AA is :

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Solution

Key Concepts and Formulas

  • Median of a Triangle: A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side.
  • Vector Representation of a Median: If AB\overrightarrow{AB} and AC\overrightarrow{AC} are two vectors representing sides of a triangle originating from vertex AA, the vector representing the median from AA to the midpoint of BCBC, denoted as AM\overrightarrow{AM}, is given by AM=12(AB+AC)\overrightarrow{AM} = \frac{1}{2}(\overrightarrow{AB} + \overrightarrow{AC}).
  • Magnitude of a Vector: The magnitude (or length) of a vector v=xi^+yj^+zk^\vec{v} = x\widehat{i} + y\widehat{j} + z\widehat{k} is given by v=x2+y2+z2|\vec{v}| = \sqrt{x^2 + y^2 + z^2}.

Step-by-Step Solution

  1. Identify the Given Vectors: We are provided with two vectors that represent the sides of triangle ABCABC originating from vertex AA:

    • AB=3i^+4k^\overrightarrow{AB} = 3\widehat{i} + 4\widehat{k}
    • AC=5i^2j^+4k^\overrightarrow{AC} = 5\widehat{i} - 2\widehat{j} + 4\widehat{k} We can explicitly write the components of AB\overrightarrow{AB} as 3i^+0j^+4k^3\widehat{i} + 0\widehat{j} + 4\widehat{k} for clarity in vector addition.
  2. Determine the Vector Representing the Median from A: Let MM be the midpoint of the side BCBC. The median through vertex AA is the line segment AMAM. In vector form, the vector representing this median is AM\overrightarrow{AM}. Using the formula for the median vector originating from a common vertex: AM=12(AB+AC)\overrightarrow{AM} = \frac{1}{2} (\overrightarrow{AB} + \overrightarrow{AC}) This formula is derived from the midpoint formula in vector form. If AA is the origin, then the position vector of MM is the average of the position vectors of BB and CC. When AB\overrightarrow{AB} and AC\overrightarrow{AC} are given, they correspond to the position vectors of BB and CC relative to AA.

  3. Substitute the Given Vectors into the Median Formula: We substitute the given vectors AB\overrightarrow{AB} and AC\overrightarrow{AC} into the formula derived in Step 2: AM=12((3i^+0j^+4k^)+(5i^2j^+4k^))\overrightarrow{AM} = \frac{1}{2} \left( (3\widehat{i} + 0\widehat{j} + 4\widehat{k}) + (5\widehat{i} - 2\widehat{j} + 4\widehat{k}) \right)

  4. Perform Vector Addition: Add the corresponding components of the vectors inside the parentheses: AM=12((3+5)i^+(02)j^+(4+4)k^)\overrightarrow{AM} = \frac{1}{2} \left( (3+5)\widehat{i} + (0-2)\widehat{j} + (4+4)\widehat{k} \right) AM=12(8i^2j^+8k^)\overrightarrow{AM} = \frac{1}{2} \left( 8\widehat{i} - 2\widehat{j} + 8\widehat{k} \right)

  5. Multiply the Resulting Vector by the Scalar 12\frac{1}{2}: Distribute the scalar 12\frac{1}{2} to each component of the vector obtained in Step 4: AM=(82)i^+(22)j^+(82)k^\overrightarrow{AM} = \left(\frac{8}{2}\right)\widehat{i} + \left(\frac{-2}{2}\right)\widehat{j} + \left(\frac{8}{2}\right)\widehat{k} AM=4i^1j^+4k^\overrightarrow{AM} = 4\widehat{i} - 1\widehat{j} + 4\widehat{k} This is the vector representing the median from vertex AA.

  6. Calculate the Length (Magnitude) of the Median Vector: The length of the median is the magnitude of the vector AM\overrightarrow{AM}. We use the formula for the magnitude of a vector: AM=(x)2+(y)2+(z)2|\overrightarrow{AM}| = \sqrt{(x)^2 + (y)^2 + (z)^2} Substituting the components of AM\overrightarrow{AM}: AM=(4)2+(1)2+(4)2|\overrightarrow{AM}| = \sqrt{(4)^2 + (-1)^2 + (4)^2} AM=16+1+16|\overrightarrow{AM}| = \sqrt{16 + 1 + 16} AM=33|\overrightarrow{AM}| = \sqrt{33}

Common Mistakes & Tips

  • Incorrect Median Formula: Ensure you are using the correct formula for the median vector, especially when the given vectors originate from the same vertex. Avoid formulas for medians from other vertices.
  • Algebraic Errors: Pay close attention to signs and arithmetic during vector addition and scalar multiplication. A small error can lead to an incorrect final answer.
  • Magnitude Calculation: Double-check the squaring and summing of components when calculating the magnitude. Remember to include the squares of all components, including the j^\widehat{j} component, even if it appears to be zero in the initial problem statement.

Summary

The problem asks for the length of the median through vertex AA of a triangle ABCABC, given the vectors AB\overrightarrow{AB} and AC\overrightarrow{AC}. We first established the vector formula for the median AM\overrightarrow{AM} originating from AA as 12(AB+AC)\frac{1}{2}(\overrightarrow{AB} + \overrightarrow{AC}). By substituting the given vectors and performing vector addition and scalar multiplication, we found the median vector to be 4i^j^+4k^4\widehat{i} - \widehat{j} + 4\widehat{k}. Finally, we calculated the magnitude of this vector, which represents the length of the median, yielding 33\sqrt{33}.

The final answer is \boxed{\sqrt{33}}.

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